Homework Statement
http://tinyurl.com/cercnq3
Homework Equations
V = IR
The Attempt at a Solution
I don't even know how to begin. Am I supposed to use superposition? I rad about it online but don't know how to apply it.
Homework Statement
http://ft.trillian.im/b0f9eae6eee2cb82091d0bd460ed09948b0cf819/6bh6EcByYLCp8YJWVJ5pqqnrqKcIY.jpg
Homework Equations
Fx= Fcos(theta)
Fy=Fsin(theta)
The Attempt at a Solution
Starting with number one, I can't understand how to find the force given by that...
First off let me just say you've been a big help, and thank you for taking time out to help me understand this stuff.
Just going to throw this out. Q = (TL)/R It makes sense in my head but it's just a guess.
oooooh. Didn't look down there.
V = 0 @ r=b
Change in V = V - where v = 0 ?
so...
V =...
Gotcha on the first part. thanks
I don't quite understand. So Q = TL can only be used for between the cylinders?
So when r<a, otherwise known as within the inner cylinder, it must depend on r? So I replace L with r? Maybe I have the wrong understanding of what exactly represents..ughhh.
I...
Is ΔV = ∫E*dr correct? Wikipedia has it with a negative, but I can't seem to understand why.
I realize now everything with E is constant except for r.
V = T/(2∏E0) * ∫(1/r)dr
V = T/(2∏E0) * ln(r)*r
So V = [Tr/(2∏E0)]*ln(r)
b) a < r < b
This is between the two cylinders. I'm...
Well, I feel like I have all the information and formula in my head somewhere. Just need some guidance sorting it all out. Haha
So, upon further review, I see that the line integral should be negative. I can't conceptually understand why though. The field is going from the inner cylinder (+) to...
Ok So...
∫E*da = q/E0
EA = q/AE0
E = q/(2∏rLE)0
Q enclosed isn't given so I assume I get that from the charge per unit length. (charge per unit length = q/L)
I will use T as charge per unit length.
Q = T*L
So:
E = T/(2∏rE0)Hopefully I'm not doing unnecessary work...from here...
ΔV = ∫E*dl
V =...
Homework Statement
http://ft.trillian.im/b0f9eae6eee2cb82091d0bd460ed09948b0cf819/6b66r5cGJrRSOCQPbItbRmtMARJhR.jpg
Homework Equations
http://ft.trillian.im/b0f9eae6eee2cb82091d0bd460ed09948b0cf819/6b674JdPpi29mGe8SqWkcnh8K6bmA.jpg
The Attempt at a Solution
I know how it works...
Homework Statement
2 Questions.
1)Find an equation for the surface consisting of all points P for which the distance from P to the x-axis is 5 times the distance from P to the yz-plane.
2)Find an equation for the surface consisting of all points that are equidistant from the point (−3...
And I got the wrong answer. My moments from that point using the two methods are not equal.
I found the moment using x and y components timers perpendicular distance is equal to 52000.
Using the second method, I found it to be 63879.
I feel like I did the first method fine.
For the second...
I have it drawn out but I'm stuck though it seems obvious...
I mean, it's just those 2 vectors with that theta in between. But you can't find the other magnitude with just one angle and one vector...
Or do the two connect at their tips to form a right angle of some sort?
Homework Statement
By finding angles, determine the component of the force acting at C which is perpendicular to the line CP. Show that the resulting moment agrees with the calculation in part (ii), if you were to look at that force alone.
Force at C = 200Ni + 250Nj (calculated to be at an...