Recent content by Keithkent09

I figured it out using a different set of equations. Thanks for your help though, sorry to waste your time.

It gave me the wrong answer. I guess that is not the correct way to find the torque

Homework Statement A 1.65 kg mass is attached to a light cord that is wrapped around a pulley of radius 4.65 cm, which turns with negligible friction. The mass falls at a constant acceleration of 2.40 m/s2. Find the moment of inertia of the pulley. Homework Equations I=mr^2 Torque=I*alpha...

Sorry I meant that it is 16/sin(alpha). This is because the vertical component of T_1 is 16 because of w_1. So using trig T_1=17.447. I am doing this the correct way and just making some kind of simple mistake?

Homework Statement Find θ and W in the figure below where w1 = 16.0 N, w2 = 25.0 N, and α = 66.5°, assuming that the arrangement is at rest. Homework Equations T_1=25/sin(alpha) F_x=-T_1cos(alpha)+T_2cos(theta) F_y=T_1sin(alpha)+T_2sin(theta)-2 The Attempt at a Solution I tried to...

Earlier I said that the denominator was sqrt(b^2+(a+x)^2) i do not understand why the placement of x=0 changes that up.

is it just the integral of (k*lambda*dx)/(sqrt(a^2+b^2) from a to a+L?

Will the limits be from 0 to a+L? Also if x=0 under point P how does that make the integral any easier, does that mean that x is thrown out in the integral and all that remains is the dx?

the integral of (k*dq)/r=(k*lambda+dx)/r r=sqrt(b^2+(a+x)^2) so... k*lambda*dx/(sqrt(b^2+(a+x)^2))...and was not sure what to do after this

The thin, uniformly charged rod shown in the figure below has a linear charge density λ. Find an expression for the electric potential at P. (Use k_e for ke, lambda for λ, a, b, and L as necessary.) Homework Equations dV=k*dq/r lambda*dx=dq The Attempt at a Solution I integrated...

Okay, I tried to use the two kinematics already but had no success. I only have two equations and three variables. I tried to substitute v_icostheta for the v_i in the x direction and v_isintheta for the v_i in the y direction and could not get anything to work. I am sorry I really am trying to...

Homework Statement In the game of darts, the player stands with feet behind a line 2.36 m from a dartboard, with the bull's-eye at eye level. Suppose you lean across the line, release a dart at eye level 2.23 m from the board, and hit the bull's-eye. Find the initial velocity of the dart, if...

Four closed surfaces, S1 through S4, together with the charges -2Q, Q, and -Q are sketched in the figure below. (The colored lines are the intersections of the surfaces with the page.) Find the electric flux through each surface. (Use Q for the charge Q and epsilon_0 for 0.) (Picture Attached)...

Do I include the negative signs for the charges or is it the absolute value of those charges I cannot remember?

Alright good. I got x=.57. This does not seem to be the right answer and I think this leaves me to be in between the two charges instead of to the left of them. What is the next step or did I do something incorrectly again?