Laws of Motion with Static Equilibrium

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SUMMARY

The discussion focuses on solving for the angles θ and the tension W in a static equilibrium problem involving two weights, w1 = 16.0 N and w2 = 25.0 N, with an angle α = 66.5°. The equations used include T_1 = 25/sin(α) and the force balance equations F_x and F_y. The correct tension T_1 is calculated as 17.447 N based on the vertical component of w1. Participants emphasize the importance of correctly applying trigonometric principles in static equilibrium scenarios.

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  • Understanding of static equilibrium principles
  • Proficiency in trigonometric functions and their applications
  • Familiarity with tension in ropes and pulleys
  • Knowledge of force balance equations in physics
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  • Study the derivation and application of force balance equations in static systems
  • Learn about the role of tension in pulley systems and how it affects equilibrium
  • Explore advanced trigonometric applications in physics problems
  • Practice solving static equilibrium problems with varying weights and angles
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Students studying physics, particularly those focusing on mechanics and static equilibrium, as well as educators seeking to enhance their teaching of these concepts.

Keithkent09
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Homework Statement


Find θ and W in the figure below where w1 = 16.0 N, w2 = 25.0 N, and α = 66.5°, assuming that the arrangement is at rest.

Homework Equations


T_1=25/sin(alpha)
F_x=-T_1cos(alpha)+T_2cos(theta)
F_y=T_1sin(alpha)+T_2sin(theta)-2

The Attempt at a Solution


I tried to use the above equations to solve for the three unknowns. First I found the tension of the string on the left, then plugged that into the second two equations to find the remaining values and I could not get the correct answers.
 

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Keithkent09 said:
T_1=25/sin(alpha)

Why is this true? What are tensions T1 and T2 in each rope?
 
Sorry I meant that it is 16/sin(alpha).
This is because the vertical component of T_1 is 16 because of w_1. So using trig T_1=17.447. I am doing this the correct way and just making some kind of simple mistake?
 
A pulley changes the direction of the tension without changing its magnitude. What is the tension in the piece of the leftmost rope that is hanging straight down?
 

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