Recent content by kholdstare121

The final equation I end up getting is 0=-4.9m/s^2*t^2-7.0m/s*t-12m When I solve that using the quadratic formula I get the squareroot of a negative number. What am I doing wrong?

we've never learned that equation :confused: :frown: Edit* But I had the same idea, I just am confused about the balloon's displacement Would it be 12m+7.0m/s*t??

acceleration/velocity word problem help! The problem is: A hot air balloon is ascending straight up at a constant speed of 7.0 m/s. when the balloon is 12.0 m above the ground, a gun fires a pellet straight up from ground level with an initial speed of 30.0 m/s. Along the paths of the...

Yeah, I got through my physics h.w. much easier after having that cleared up. thanks

Actually nevermind! I did some research and found out that if an object is going in the positive direction and Deccelerating, then the sign of the acceleration is opposite of the direction. I think that's right?

acceleration: screwed up vector?? I need things cleared up when it comes to acceleration. Is acceleration negative when it points in a certain direction...or when an object is slowing down? I was working on a free falling bodies word problem: A diver springs upward with an initial speed of 1.8...

Thanks that helped out a lot, figured it out! I have a test on this chapter Tuesday, and these trig limits might just kill me. There are so many identities to use, so little time.

I don't know if this neccessarily belongs in the calculus section, but it's for my calculus class. How would you go about finding the limit as x approaches 0 for (1-cos(x))/2sin^2(x) I know the answer is 1/4(unless I copied it down wrong :/ ) , but what first steps would you take to evaluating...

Oh wow! I feel REALLY dumb right now. Was the solution that simple? I just worked it out and got the right answer(so it is that simple :smile: ) I was going through every other equation, missing the easy connection with this one. Thanks a lot :smile:

I'm taking high school physics right now, and we're doing kinematics in one dimension. Well I've been stuck on this word problem for days and stumbled across this forum on a google search. Thought maybe you could help. Anyway it is: --------------------------------------------------------------...