Recent content by kmj9k

I believe so. In the book it says to take into account in which medium the diffraction pattern is observed.

I tried dividing 0.7112 m by 720 and got 9.8778e-4. I then plugged that into the L = y/ (tan theta min)) and got 11.99, which is still incorrect...

[b]1. The American Television Systems Committee (ATSC) sets the standards for high-definition television (HDTV). One of the approved HDTV formats is 720p, which means 720 horizontal lines scanned progressively - one line after another in sequence. Suppose the 720 lines are displayed on a...

OK, inverting the shutter speed makes it much more easy to understand! I get the problem now and got the right answers. Thank you very much for your help!

Yes, I understand that part...you want the same amount of light / photons. I thought the answer to (a) might be 1/375, to make the shutter speed 3x faster so that less light is able to get in and the photo is 1/3 as bright. But, I know that's wrong...

You are taking pictures of the beach at sunset. Before the Sun sets, a shutter speed of 1/125 s at f/11 produces a properly exposed picture. Shortly after the Sun sets, however, your light meter indicates that the scene is only one third as bright as before. (a) If you don't change the...

[b]1. A 8.6 Hz generator is connected to a capacitor. If the current in the generator has its maximum value at t=0 s, what is the earliest possible time that the voltage magnitude across the capacitor is at a maximum? [b]2. I'm actually not sure which equations are relevant for this...

I got it! I used B*Area (or BVL) times the cos of 108 and got 0.397 mV. Thank you so much for your help!

A car with a vertical radio antenna 75 cm long drives due east at 29 m/s. The Earth's magnetic field at this location has a magnitude of 5.9* 10^-5 T and points northward, 72° below the horizontal. (b) Find the induced emf between the ends of the antenna. Relevant Equations: E = BVL...

Oooh I see now. I wasn't thinking of the cross products of vectors correctly (ie, I was thinking of the magnetic field as a scalar). Remembering that it's 0.81 *Z* I got -2187x + 2673y for the electric field using the equation above and got it right. Thanks so much to all the posters for...

Hmm I'm more confused than ever. I realize that E will have x, y and z components...but how do I get there? I'm sorry, I think I'll need step-by-step assistance. I think the vectors aspect is the big stumbling block for me.

A charged particle moves through a region of space containing both electric and magnetic fields. The velocity of the particle is v = (3.3 x 10^3 m/s) x + (2.7 x 10^3 m/s) y and the magnetic field is B = (0.81 T) z. Find the electric field vector E necessary to yield zero net force on the...

My equation was mgh = (1/2)mv^2, where v = the square root of 2gh. I got 5.4249 m/s. And then for the second part, even if you didn't find the time t, couldn't you also just use the kinematic equations for projectile motion at zero degrees? ie, x= initial V* square root of (2h)/g ?

This is the latest question I've been stuck on. The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the n=2 orbit, the distance from the proton to the electron is 21.16e-11 m , and the linear speed of the...

Hi, I've been struggling with this problem and would appreciate any help: A 1.8 kg block slides down a frictionless ramp, as shown in Figure 8-28. The top of the ramp is 1.5 m above the ground; the bottom of the ramp is h = 0.20 m above the ground. The block leaves the ramp moving...