How Close Can You Get to a 720p TV Before Seeing Individual Lines?

  • Thread starter Thread starter kmj9k
  • Start date Start date
  • Tags Tags
    Optics Resolution
AI Thread Summary
The discussion centers on calculating the minimum viewing distance for a 720p TV based on its resolution and the human eye's ability to perceive detail. The American Television Systems Committee defines 720p as having 720 horizontal lines, and the calculations involve Rayleigh's Criterion to determine the closest distance before individual lines become visible. The initial calculations for theta min and the subsequent distance L yielded incorrect results, prompting questions about the use of the diffraction coefficient and the separation of lines on the screen. Participants suggest that the separation of horizontal lines should be calculated based on the screen's dimensions rather than using a fixed value. The conversation emphasizes the importance of accurately applying optical principles to achieve the correct minimum viewing distance.
kmj9k
Messages
15
Reaction score
0
1. The American Television Systems Committee (ATSC) sets the standards for high-definition television (HDTV). One of the approved HDTV formats is 720p, which means 720 horizontal lines scanned progressively - one line after another in sequence. Suppose the 720 lines are displayed on a television with a screen that is 28 inches high, and that the light coming from the screen has a wavelength of 505 nm. If the pupils of your eyes have a diameter of 5.5 mm, what is the closest you can be to the TV before seeing the individual horizontal lines? (This is the minimum acceptable viewing distance.) 2. Rayleigh''s Criterion: theta min = 1.22 (lambda/D); L = (y/ (tan theta min))

3. To find theta min, I did 1.22 ((505*10^-9)/1.36)/0.0055) and got 8.237 * 10^-5 rad. I divided the wavelength by 1.36 since that is the index of diffraction for the eye. Then, I plugged it into the L = equation: L= 0.7112 m /tan (8.237*10^-5) and got a final answer of 8634, which is incorrect.

Where did I go wrong? Thank you!
 
Physics news on Phys.org
I don't think you should be using y = 0.7112 m. You want to find the separation of two of the horizontal lines, which you can figure out because you know how many lines are in the 28" screen.
 
I tried dividing 0.7112 m by 720 and got 9.8778e-4. I then plugged that into the L = y/ (tan theta min)) and got 11.99, which is still incorrect...
 
Are you sure about that diffraction coefficient you are using? Perhaps it is not necessary.
 
I believe so. In the book it says to take into account in which medium the diffraction pattern is observed.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top