Recent content by kpangrace

You are trying to photograph a bird sitting on a tree branch, but a tall hedge is blocking your view. However, as the drawing shows, a plane mirror reflects light from the bird into your camera. If x = 3.1 m and y = 4.0 m in the drawing, for what distance must you set the focus of the camera...

A computer to be used in a satellite must be able to withstand accelerations of up to 32 times the acceleration due to gravity. In a test to see if it meets this specification, the computer is bolted to a frame that is vibrated back and forth in simple harmonic motion at a frequency of 11.4 Hz...

When a charged particle moves at an angle of 19° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.8F? can...

Nevermind i figured it out, its sin(60), not sine of 30 or 90... you can kill this thread if you wish!

:rolleyes: The two conducting rails in the drawing are tilted upwards so they make an angle of 30.0° with respect to the ground. The vertical magnetic field has a magnitude of 0.048 T. The 0.22 kg aluminum rod (length = 1.6 m) slides without friction down the rails at a constant velocity. How...

would i just do it as I=12/9 = 1.333 to get the current running through it? i assumed that because htere's both parallel and series circuits that they first wanted me to combine them all to practice that or whatever... hmmm the first problem on my homework page and the last one i need

9+1= 10 ohm 2+1= 3 ohm 1/10 + 1/3= 1/r=2.308 2.308+3= 5.308 ohms v=12 I= V/R I= 12/5.308 I=2.261 did i not add the resistors correctly?

Determine the power dissipated in the 9.0 resistor in the circuit shown in the drawing. (R1 = 3.0 , R2 = 9.0 and V1 = 12 V.) ok here's my problem... I've found the current throughout to be 2.261 a... now if i use that to find the voltage in the 9 ohm resistor, i get a voltage bigger...

how did you figure out the first part? i have close to the same problem but with different values, but i am kind of lost

hmmm i went through and did everything you said and i got 3.881 e10... which seemed way off and it was... there was something i obviously did wrong, what was it? and thank you for your help

Speed of a proton? i just don't know where to start with this? do i have to go back to basic physics?? i tried using the charge of the single proton to find the force of the electric field, and then with that force find an acceleration maybe? I am way confused A uniform electric field...

ok i put (1/2)v^2= 1/2 v^2 + gh now is that right? i plug everything in and get .957... which doesn't show up right... you know what I'm doing wrong? thanks in advance

Help! Only Have Until 11:30 A bowling ball encounters a 0.76 m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. If the translational speed of the ball is 4.10 m/s at the bottom of...

how would i switch something like 10.464 rad/s^2 to m/s^2 i know its easy but I've got a brain fart

Final problem, need help! A race car, starting from rest, travels around a circular turn of radius 24.5 m. At a certain instant, the car is still accelerating, and its angular speed is 0.521 rad/s. At this time, the total acceleration (centripetal plus tangential) makes an angle of 35.0° with...