Homework Statement
Hi, I have the following task:
We have two conformers and the difference in energy between them is aprox. 1 Kcal/mol. What is the Keq at room temperature vs. at -78°C?
Homework Equations
Keq=e^(deltaG/(-R*T))The Attempt at a Solution
I tried to solve the problem the...
Hello,
thank you for helping me.
I tried to do that and obtained the following:
If this is correct, I still don't see what I have to do in the next step and when I have to use a program.
Homework Statement
Hello, I have the following task:
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Homework Equations
In the task[/B]
The Attempt at a Solution
I looked at this task with the notes from the class, but I can't really see through. It seems that the first step is the transformation into the single decoupled...
Homework Statement
Hi, my task is to show that the momentum operator is hermitian.
I found a link, which shows how to solve the problem:
http://www.colby.edu/chemistry/PChem/notes/MomentumHermitian.pdf
But there are two steps that I don't understand:
1. Why does the wave function approach...
Oh i thought that the 3 bar were at the beginning, so I converted everything in SI units and used p*V=n*R*T to get the volume. Then i converted the volume in liters, and divided the starting amount of moles to get the mol/l which I used to calculate the values
When I try it that way, I get 0.019M for PCl5 at the end and 0.05M for each of the resulting substances. Therefore the dissociation degree of PCl5 would be 73% since the start amount was 0.069M. Do these values make sence?
Homework Statement
The task is the following:
If the concentration of A decreases 0.03 M in one hour, then the concentration of B should to, which means, [ B] should be 0.05 M?
And if I try to calculate k, i get 14.87 l/(mol*h)
For second order reactions, t1/2 sould be 1/(k*[A]0)
So I get...
Homework Statement
I have the following task:
A chemical reaction 2 A(g) <-> B(g) + C(g)
has an equilibrium constant defined by: ln=0.8+ 1050/T−1,3.105/T²
a) What is K at 400K? Calculate ΔrG0
In a volume of 5L you get 2 moles of A and 0.5 moles of B. Reaction still proceeds at 400K. Consider...