Recent content by learningastronomy

Oh I see, I may need to revisit the definition of macrostate then because I was thinking of a different interpretation of it. Also, the total different possibilities will be 40+1 therefore 41.

Hmm can you please elaborate why it is 41 macro states?

Ops, I meant to say ##2^{40}## not ##40^2##, thanks for catching that.

Since this is a two-state paramagnet where N = 40, therefore the microstate is ##40^2##? But I am not sure how to proceed to count the number of macrostates? Because from what I understand of what a macrostate is, shouldn't there a specific outcome to be stated in order to determine how many...

Oh I see, thank you!

The process does not have to be Poisson, I just assumed to use Poisson to compute the uncertainty. If there was only one trial in the experiment how do I solve for the uncertainty/error bars? Will Poisson suffice even though the uncertainty is so small it becomes insignificant?

From what I understand thus far is the counting involves Poisson therefore the uncertainty is just the square root of the counts, correct? But when I take the square root of the counts it produces a very small number compared to the count which makes it insignificant therefore the error bars...

For example suppose the uncorrected extinction instrumental magnitude is ##v^A_V = 9.00##, will the corrected extinction instrumental magnitude always be greater than ##9##?

Anyone know a good book that talks about this topic in detail?

Ops sorry I didn't know this wasn't the right thread for this question. But yes please move this thread.

Summary:: Finding the corrected coefficients Suppose you obtained the following magnitude results based off your observations from standard stars: ##\kappa_0 = 0.65##, ##\kappa_1 = 0.10##, ##\alpha_0 = 2.00##, ##\alpha_1 = 0.05##, where ##\kappa_0,\kappa_1## are the extinction coefficients and...

I thought the equation was magnitude times the count? Or does the magnitude need to be inside the square root?

Hmm which brackets?

Yes, the scope is only Poisson. So the count rate for part b will be different due to the change of magnitude? So since the magnitude difference is ##4## will I get the following: $$2.5^4 * \sqrt\frac{400}{\frac{60sec}{10sec}}?$$

Summary:: An image was taken with a ##60## second exposure time of a 6th magnitude star and the signal to noise ratio was detected to be ##S/N = 20##. a. What should the exposure time be if you wanted a ##S/N = 100##? b. Now calculate the ##S/N## if it were a 2nd magnitude star for a ##10##...