Determine how many microstates and macrostates (Thermodynamics)

AI Thread Summary
In a two-state paramagnet with N = 40, the number of microstates is correctly identified as 2^40, reflecting all possible configurations of the system. The discussion clarifies that macrostates are determined by the total magnetic dipole moment, leading to 41 distinct macrostates, ranging from 0 heads to 40 heads in the coin analogy. The confusion arises from the interpretation of macrostates, which are defined by macroscopic properties rather than specific configurations. The formula for counting macrostates is linked to the total number of possible outcomes, hence the total is 40 + 1. Understanding the definition of macrostates is crucial for accurate calculations in thermodynamics.
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Homework Statement
A two-state paramagnet has 40 magnetic dipoles. Determine the amount of microstates and macrostates?
Relevant Equations
##\Omega(N,n)=\frac{N!}{n!(N-n)!}## or ##\omega(N_{\uparrow})=\frac{N!}{N_{\uparrow}!N_{\downarrow}!}##
Since this is a two-state paramagnet where N = 40, therefore the microstate is ##40^2##? But I am not sure how to proceed to count the number of macrostates? Because from what I understand of what a macrostate is, shouldn't there a specific outcome to be stated in order to determine how many macrostate there are? For instance suppose we have 40 coins then the number of microstate (all different states of heads and tails) will be ##40^2## but in order to compute macrostate then you will have to explicitly provide the state it is in, for example determine the amount of macrostate of the 40 coins that only have two heads then you can use $$\Omega(N,n)=\frac{N!}{n!(N-n)!}$$ $$\therefore\Omega(40,2)=\frac{40!}{2!(40-2)!}=780?$$ And since the question didn't explicitly provide the macrostate then will it just be the general case of $$\Omega(40,n)=\frac{40!}{(40-n)!}?$$

Is my reasoning correct?
 
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learningastronomy said:
Is my reasoning correct?
I don't think so. Not my area but this might help.

You have 3 coins in a line. How many head-tail patterns are possible? (It's not 3².) What about 40 coins (it's not 40²)?

As for macrostates, I would assume the macrostates are simply (continuing the 40-coin example):
0 heads, 40 tails
1 head, 39 tails
2 heads, 38 tails
etc.
 
there are 41 macro states total. A macro state is different from each other by its macroscopic properties in this case it would be the total magnetic dipole moment.
learningastronomy said:
Homework Statement:: A two-state paramagnet has 40 magnetic dipoles. Determine the amount of microstates and macrostates?
Relevant Equations:: ##\Omega(N,n)=\frac{N!}{n!(N-n)!}## or ##\omega(N_{\uparrow})=\frac{N!}{N_{\uparrow}!N_{\downarrow}!}##

Since this is a two-state paramagnet where N = 40, therefore the microstate is ##40^2##? But I am not sure how to proceed to count the number of macrostates? Because from what I understand of what a macrostate is, shouldn't there a specific outcome to be stated in order to determine how many macrostate there are? For instance suppose we have 40 coins then the number of microstate (all different states of heads and tails) will be ##40^2## but in order to compute macrostate then you will have to explicitly provide the state it is in, for example determine the amount of macrostate of the 40 coins that only have two heads then you can use $$\Omega(N,n)=\frac{N!}{n!(N-n)!}$$ $$\therefore\Omega(40,2)=\frac{40!}{2!(40-2)!}=780?$$ And since the question didn't explicitly provide the macrostate then will it just be the general case of $$\Omega(40,n)=\frac{40!}{(40-n)!}?$$

Is my reasoning correct?
 
Steve4Physics said:
I don't think so. Not my area but this might help.

You have 3 coins in a line. How many head-tail patterns are possible? (It's not 3².) What about 40 coins (it's not 40²)?

As for macrostates, I would assume the macrostates are simply (continuing the 40-coin example):
0 heads, 40 tails
1 head, 39 tails
2 heads, 38 tails
etc.

Ops, I meant to say ##2^{40}## not ##40^2##, thanks for catching that.
 
guv said:
there are 41 macro states total. A macro state is different from each other by its macroscopic properties in this case it would be the total magnetic dipole moment.
Hmm can you please elaborate why it is 41 macro states?
 
learningastronomy said:
Hmm can you please elaborate why it is 41 macro states?
@guv is saying that a macro state is defined by its total dipole moment. How many different possibilities are there for that total?
 
haruspex said:
@guv is saying that a macro state is defined by its total dipole moment. How many different possibilities are there for that total?
Oh I see, I may need to revisit the definition of macrostate then because I was thinking of a different interpretation of it. Also, the total different possibilities will be 40+1 therefore 41.
 
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learningastronomy said:
Oh I see, I may need to revisit the definition of macrostate then because I was thinking of a different interpretation of it. Also, the total different possibilities will be 40+1 therefore 41.
Macrostates are whatever matters to you in a particular context. For the result of a tennis match, we might only care who won, or we might care what the individual set scores were, etc.
 
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