Recent content by libelec

Thank you very much.

I understand. So it would be something like: Vc = V1 + (V2 - V1) * e-t/τ Is this correct? One final question: the total R in this circuit, is it 10100ohm?

The problem is that the previous voltage over the capacitor is the one it has in its stationary while the switch L1 is closed. Then when its opened, is when the experiment begins. So that rule for the voltage over the capacitor isn't valid for the previous situation while it is loading at the...

Nobody?

Yeah, sorry. V(a) isn't supposed to be a a source, it was just the only way I had to draw it. This is the circuit written on the assignment, I'll edit it: Pay no attention to the rest of the circuit. Just the bottom half.

Homework Statement Find V(a) as a function of time in the following circuit when the switch is opened. Originally, the capacitor is charged to Vc = 1/101 * V1. The Attempt at a Solution I know that when the switch is opened, the capacitor is going to get charged again, and V(a) is going to...

I don't see what difference it makes. The relation is one is half of the other wheather I print 6 or 10 digits. I mean, if I give it larger precision, it may go from printing 0.06666 and 0.03333 to 0.066661234 and 0.033334564. EDIT: I think I see what you may be missing: my second post only has...

I changed the code to reflect the tips you gave regarding the cross-type operations: long double rungeKutta(long double h) { long double alpha = 6629.0; long double beta = 0.0047; long double pos = 39068.0; long double speed = 0; for (double i = 1; h*i < 120.0; i++) { long double k1v =...

(DISCLOSURE: I have already posted this problem in http://math.stackexchange.com/questions/256393/calculate-runge-kutta-order-4s-order-of-error-experimentally, but found no satisfactory answer) The problem is this. I need to experimentally check that RK4 method has an error of order 4...

Anybody?

Homework Statement Let U = 0.X1X2X3... be a random number in (0,1]. 1) Find the distribution of every decimal digit Xi, i = 0,1,2... 2) Show that they are independent of each other The Attempt at a Solution I could use a hint for N°2. I have an idea, but I think it's wrong...

So the likelihood function is (p/6)*(1-(p-1)/5) 1{p=1,...,5}. The prior function of p is then 1/7 1{p=0,1,...,6} Then \Pi(p|BW) = (1/7*(p/6)*(1-(p-1)/5)1{p=1,...,5})/(\sum1/7*(p/6)*(1-(p-1)/5)) This I solved as: \Pi(p|BW) = 6/7*(p/6)*(1-(p-1)/5)1{p=1,...,5} So, that's the posterior...

I mean 1 - (p-1)/5. Is that it?

Oh, you're right: there's no replacement. So, should I treat the X's as Bernoulli variables or as hypergeometric variables? I mean, if now p is the number or white balls in the urn, the sample yields (p/6)*(1-p/5)?

Homework Statement An urn has 6 balls: black and white. Initially, the number of white balls W is distributed uniformly in {0,1,...,6}. Two balls are taken from the urn: one white and one black. Find the distribution of W before the experiment. The Attempt at a Solution So, initially...