Recent content by lolzwhut?

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    Questions about emission spectra and Rhydberg equation for H-atom

    My experimental data must have been wrong..What I've calculated is 100% right.
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    Questions about emission spectra and Rhydberg equation for H-atom

    I actually figured it out... Here's my work: a. R((1/2^2)-(1/3^2)) = .00152 = 1/.00152 = 657.89 nm b. R((1/2^2)-(1/4^2)) = .00205 = 1/.00205 = 487.80 nm c. R((1/2^2)-(1/5^2)) = .00230 = 1/.00230 = 434.78 nm d. R((1/2^2)-(1/6^2)) = .00243 = 1/.00243 = 410.21 nm
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    Questions about emission spectra and Rhydberg equation for H-atom

    There's no way to predict that..Here's what I'm thinking is right: 1/pi = R(1/nf - 1/ni) R = 109737 cm nf = 750 nm = 7.5*10^-5 CM ni = 490 nm = 4.9*10^10-9 CM So... 1/pi = 109737 (1/(7.5*10^-5) - 1/(4.9*10^-9)) = 1/pi = -2.23*10^13 UGHhhh...what the heck! I JUST DONT GET...
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    Questions about emission spectra and Rhydberg equation for H-atom

    Bump. I've figured everything out. But can't still solve this question: "Using the Rhydberg equation, calculate the transitions in the H-atom that are taking place to give rise to each line." If you look at my data, it has 7 lines...Shouldn't I just be calculating it from the highest line I...
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    Questions about emission spectra and Rhydberg equation for H-atom

    Homework Statement I'm just curious to if I have answered this questions properly, and was wondering if someone can see if I should add more to what I have written, or completely change my answer. I'm pretty confident with what I've answered, but would like someone to check :) So to begin...
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    This online chemistry lab won't accept my answer, WHY?

    Hmmm...your work seems right to me. maybe you typed it wrong?
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    Basic Dimensional Analysis Question

    Wow, so 7.74 cm^2 is what I'm getting. Thanks for the help guys. I definitely won't forget my units this time xD But yeah, I got 7.74 cm^2.
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    Basic Dimensional Analysis Question

    1. Convert 1.2 in^2 to cm^2 2. 1 CM = 10^-2 and 1 inch = 2.54 centimeteres The Attempt at a Solution Can't we just do 1.2*2.54=3.048 and write that as our answer?
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    Is My Procedure for Calculating Water Density in a Chemistry Lab Correct?

    Just curious, but why are we dividing by 10? FYI, I'm taking the temperature in Fahrenheit.
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    Mean, Deviation (DEV), and Average (DEV)? question

    For the following data set of eight values, give the MEAN, DEVIATION (DEV), and AVERAGE DEVIATION (AD). Show a sample calculation for each: 0.77, 0.92, 1.12, 1.00, 0.96, 0.88, 1.16, 1.02 Homework Equations Well before we began, can anyone take the courtesy and see if I'm getting the...
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    Is My Procedure for Calculating Water Density in a Chemistry Lab Correct?

    Thanks, I was right :) I even asked the teacher, he confirmed it. Also, there's this odd question... "What does it mean when you a piece of glassware that is "graduated" or has "graduations" on it?" Couldn't we describe graduations as precise measuring marks?
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    Is My Procedure for Calculating Water Density in a Chemistry Lab Correct?

    I'm curious if I'm doing this chemistry lab correctly or not. If you open the link below, you can see the lab. Basically, my job right now is to write a well formulated procedure on how to perform this lab. So, for this lab, am I supposed to be calculating the mass of the substance (h2o in...
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    Average vs Instantaneous Rates of Change Problem

    Hello, all. I'm doing a review in the back of my Calculus book and need help on this particular problem. The book has the answer, but I don't understand how to get it. If someone can show me steps to solving this problem, it would be greatly appreciated. Problem: The distance a person can walk...
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    Electromagnetism and earth question

    Homework Statement Assume that Earth’s magnetic field is everywhere perpendicular to the path of a proton and that Earth’s magnetic field has an intensity of 4.07 × 10−8 T. What speed would a proton need to achieve in order to circle Earth 1660.0 km above the magnetic equator? Answer...
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    Conservation of energy - velocity problem

    :o, thanks a ton man. I think this was a trick question...Since I never thought of the diameter. It makes sense why its 26.7-18 instead of 9. Thanks for clearing it up, I was really starting to get a little confused there.
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