Recent content by luap12

That worked, thanks. I had the wrong idea of what the terms actually meant.

1.An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one-half the size of the object. The distance between the object and the image is 102.0 cm. (a1) How far from the lens is the object...

Thanks very much, I got it now. ((k*q)/x^2)-((k*2q)/(x+10)^2)=0, solving for x gives 24.142cm. Accounting for the distance of 5cm on the x-axis give the point to be 29.142cm. This was the correct answer. Thanks!

I don't understand what you mean by that... I think I'm over-thinking this.

[b]1. Homework Statement [http://img44.imageshack.us/img44/1104/58339946.jpg ][/URL] [b]2. Homework Equations [F=k*abs(q1)*abs(q2)/r^2] [b]3. I understand the equation, but I am having trouble with my signs and also how to include the distance in the equation. I know that the...

ok, I understand now that the velocity is not constant. I don't believe we have covered angular velocity yet in class, unless I am just overlooking it. How do you do that? I did set up a proportion though with the velocity and radius and got it correct.

1. A computer is reading data from a rotating CD-ROM. At a point that is 0.0330 m from the center of the disk, the centripetal acceleration is 264 m/s2. What is the centripetal acceleration at a point that is 0.0702 m from the center of the disc? 2. ac=v2/r 3. So my thoughts here...

that works and makes sense now! Thanks!

1. A car (m = 1940 kg) is parked on a road that rises 14.4 ° above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires? Homework Equations 3. I am not sure what I need to do here. Wouldn't the...