Why Is My Calculation of Lens Object Distance Incorrect?

AI Thread Summary
The discussion revolves around calculating the object distance from a lens given that a real, inverted image is formed. An object is placed to the left of the lens, resulting in an image to the right that is half the size of the object, with a total distance of 102 cm between them. The formula used, m = -di/do, initially led to confusion regarding the signs and values for distances. The correct interpretation of the terms clarified the calculation, leading to a better understanding of the relationship between object distance and image distance. Ultimately, the participant resolved their misunderstanding and successfully applied the concepts to the problem.
luap12
Messages
10
Reaction score
0
1.An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one-half the size of the object. The distance between the object and the image is 102.0 cm.

(a1) How far from the lens is the object?



2.m=-(di/do)



3. with the equation above I thought it was just -1/2=120/do and solving for do gives -204 cm, but this answer is wrong, and so is 204. I know that m is negative because the image is inverted. Not sure if my logic is right or not, we haven't covered this yet in class but it is still on the homework.
 
Physics news on Phys.org
M = -q/p, in which q is the distance from the lens to the image and p is the distance from the lens to the object. The 102cm given is the distance between the object and image.
 
That worked, thanks. I had the wrong idea of what the terms actually meant.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Focal length of the eyepiece lens in a compound microscope
Replies
7
Views
1K
Find the location and length of the final image
Replies
2
Views
842
Analyzing this 2-lens optical system
Replies
5
Views
1K
Mirror placed horizontally between two half convex lenses
Replies
11
Views
1K
Optics Problem with a Double Lens System
Replies
1
Views
2K
Position of the object and image in this optics problem
Replies
10
Views
2K
Optics - Adding magnification in an optical system
Replies
3
Views
2K
Magnification, when is it negative?
Replies
2
Views
10K
How Does a Combined Lens and Mirror System Create Images?
Replies
1
Views
4K
What is the focal length of the lens?
Replies
20
Views
4K

Hot Threads

Recent Insights

Back
Top