Aradesh, sorry for my slow understanding, but how do you accommodate for all movement from person 1 to then person -1, and finally person n
For example:
0>1>2>1>2>3
Have found solution but need further help! Here is my attempt:
Found PM is diameter of circle l, Triangle MCD similar to Triangle MPC, Triangle DMB similar to Triangle BMP, Angle DBM = Angle ABK.
Prove AK = KH, (using similar triangles or otherwise)
Homework Statement
In ΔABC, ∠A = 90°, M is the midpoint of BC and H is the foot of the altitude from A to BC. A circle l is drawn through points A, M and C. The line passing through M perpendicular to AC meets AC at D and the circle l again at P. BP intersects AH at K.
Prove that PM is...
ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.
Show that ME = MC