Recent content by Lukybear
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Probability question, Very hard
But say can't ball swing from 0>1 then to -1 in other direction? How is that accommodated?- Lukybear
- Post #30
- Forum: Precalculus Mathematics Homework Help
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Probability question, Very hard
Aradesh, sorry for my slow understanding, but how do you accommodate for all movement from person 1 to then person -1, and finally person n For example: 0>1>2>1>2>3- Lukybear
- Post #28
- Forum: Precalculus Mathematics Homework Help
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Prove PM is Diameter in ΔABC with ∠A = 90°
Have found solution but need further help! Here is my attempt: Found PM is diameter of circle l, Triangle MCD similar to Triangle MPC, Triangle DMB similar to Triangle BMP, Angle DBM = Angle ABK. Prove AK = KH, (using similar triangles or otherwise)- Lukybear
- Post #4
- Forum: Precalculus Mathematics Homework Help
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Prove that ME=MC in a Circle Geometry ABCD
Nvm, I've found solution. Thxs.- Lukybear
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Prove PM is Diameter in ΔABC with ∠A = 90°
Opps sorry. I want to figure out that PM is the diameter- Lukybear
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Prove PM is Diameter in ΔABC with ∠A = 90°
Homework Statement In ΔABC, ∠A = 90°, M is the midpoint of BC and H is the foot of the altitude from A to BC. A circle l is drawn through points A, M and C. The line passing through M perpendicular to AC meets AC at D and the circle l again at P. BP intersects AH at K. Prove that PM is...- Lukybear
- Thread
- Diameter
- Replies: 4
- Forum: Precalculus Mathematics Homework Help
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Prove that ME=MC in a Circle Geometry ABCD
ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N. Show that ME = MC- Lukybear
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- Circle Geometry
- Replies: 2
- Forum: Precalculus Mathematics Homework Help