I figured out what I did wrong in this situation... cos-1(0) could be either pi/2 or -pi/2, and because the motion is coming to the end of a complete cycle I should have used -pi/2.
To answer your question, I determined the phase shift=phi by solving the position equation. I knew at t=0...
Homework Statement
At t = 0 a block with mass M = 5 kg moves with a velocity v = 2 m/s at position xo = -.33 m from the equilibrium position of the spring. The block is attached to a massless spring of spring constant k = 61.2 N/m and slides on a frictionless surface. At what time will the...
Homework Statement
Find the area bounded between the two curves
y=34ln(x) and y=xln(x)
Homework Equations
Integration by parts: \intudv= uv-\intvdu
The Attempt at a Solution
First I found the intersection points of the two equation to set the upper and lower bounds. The lower...
I think the mistake you are making is in the formula that you are integrating. It seems like you were thinking washers while using the shell equation.
The general equation to use for the shell method is
2\pi\int R dx(dx can change depending on which variable you are integrating with respect...
all you have to do is multiply it to the two solutions
so say the factored quadratic is (x-4)(x+4), so the solutions are 4 and -4. just multiply the rad5 to those two answers.
because the velocity is downward it is negative, as well as the acceleration. you can't interchange them. it is just important to note the direction of the velocity depending on the equation you decide to use!
Is the initial velocity 66 or 68 m/s? If it is 68 m/s, your answer is very close to mine---I'm sure just rounding differences. Just double check the problem.