Recent content by maladroit

  1. M

    Block and Spring (Simple Harmonic Motion Problem)

    I figured out what I did wrong in this situation... cos-1(0) could be either pi/2 or -pi/2, and because the motion is coming to the end of a complete cycle I should have used -pi/2. To answer your question, I determined the phase shift=phi by solving the position equation. I knew at t=0...
  2. M

    Block and Spring (Simple Harmonic Motion Problem)

    Homework Statement At t = 0 a block with mass M = 5 kg moves with a velocity v = 2 m/s at position xo = -.33 m from the equilibrium position of the spring. The block is attached to a massless spring of spring constant k = 61.2 N/m and slides on a frictionless surface. At what time will the...
  3. M

    Area of the region bounded between two curves with integration by parts

    My mistake was in the bounds, which should have been from 1 to 34. Thank you for your help!
  4. M

    Area of the region bounded between two curves with integration by parts

    Homework Statement Find the area bounded between the two curves y=34ln(x) and y=xln(x) Homework Equations Integration by parts: \intudv= uv-\intvdu The Attempt at a Solution First I found the intersection points of the two equation to set the upper and lower bounds. The lower...
  5. M

    Cylindrical Shells

    nevermind, i've got it! sorry for my faulty answer and thank you for correcting my mistake.
  6. M

    Cylindrical Shells

    why would the limits of integration be from 1 to 3 if you are integrating with respect to the x axis?
  7. M

    Cylindrical Shells

    I think the mistake you are making is in the formula that you are integrating. It seems like you were thinking washers while using the shell equation. The general equation to use for the shell method is 2\pi\int R dx(dx can change depending on which variable you are integrating with respect...
  8. M

    Function composition

    all you have to do is multiply it to the two solutions so say the factored quadratic is (x-4)(x+4), so the solutions are 4 and -4. just multiply the rad5 to those two answers.
  9. M

    Help with classical mechanics question

    Momentum is always conserved in a closed system-that is, if there are no external forces that could effect the situation. Hope that helps!
  10. M

    Kinematics Final Velocity Question

    because the velocity is downward it is negative, as well as the acceleration. you can't interchange them. it is just important to note the direction of the velocity depending on the equation you decide to use!
  11. M

    Kinematics Final Velocity Question

    also correct! acceleration is -9.8 m/s2. something to think about--what is the direction of the velocity?
  12. M

    Kinematics Final Velocity Question

    exactly! 2 m/s would be the initial velocity.
  13. M

    Kinematics Final Velocity Question

    Glad you understand it!
  14. M

    Kinematics Final Velocity Question

    Is the initial velocity 66 or 68 m/s? If it is 68 m/s, your answer is very close to mine---I'm sure just rounding differences. Just double check the problem.
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