Recent content by MAPgirl23

Homework Statement 2 long, straight parallel wires 0.1m apart carry equal 3.78A currents in the same direction. Find the magnitude and direction of the magnetic field at a point 0.154m above one wire.Homework Equations B = (\mu0I) / (2\pir) \mu0 = 4\pi * 10-7 The Attempt at a Solution r =...

Static Equilibrium... Please help Homework Statement The J-shaped member shown in the figure is supported by a cable DE and a single journal bearing with a square shaft at A. Determine the reaction forces and at support A required to keep the system in equilibrium. The cylinder has a weight =...

mg = -Force of gravity*sin(theta)-mu_k= -mgsin(theta)-mu_k

A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x_c. The spring has spring constant k. The incline makes an angle theta with the horizontal and the coefficient of kinetic friction between the block and the...

The density of the oil is 630 kg/m^3 = 0.63 g/cm^3 The pressure from the oil is 63g/cm^2 per meter depth At 0.11 m deep the pressure from the oil at the interface is 0.11 x 63 = 6.93 g/cm^2 Water pressure is 100g/cm^2 per meter depth At 0.245 m deep the pressure from the water is...

I converted 10 cm^3 = 1.0 x 10^-5 m^3 and 40 cm^3 = 4.0 x 10^-5 m^3 v = 6.0 x 10^-3 * (1.0x10^-5/4.0x10^-5) = 1.50x10^-3 m/s ?

for part a) v2 = 6.0x10^-3 * (10 cm^3 / 40 cm^3) = 1.50x10^-3 which was wrong

http://mb.sparknotes.com/mb.epl?b=113&m=1067136&t=306821&w=1

The horizontal pipe has a cross-sectional area of 40.0 cm^2 at the wider portions and at the constriction. Water is flowing in the pipe, and the discharge from the pipe is 6.0 x 10^-3 m^3/s (6.0 L/s). a) Find the flow speed at the wide portion. b) Find the flow speed at the narrow portion...

A barrel contains a layer of oil of thickness 0.110 m floating on water of depth 0.245 m. The density of the oil is 630 kg/m^3 a) What is the gauge pressure at the oil-water interface? b) What is the gauge pressure at the bottom of the barrel? ** a) Atmospheric Pressure + Pressure...

how do I express that in cm?

If the air pressure is increased by 1500 Pa the pressure at the bottom of the container is 4000 pa If the original head of water gives a pressure of 2500 Pa and the water is to be drained to reduce the pressure from the head of water to 1000 pa Then the level is to be reduced by 1500/2500...

so is the height = 1500 Pa/(1000 * 9.81) ?

A closed container is partially filled with water. Initially, the air above the water is at atmospheric pressure 1.01x10^5 Pa and the gauge pressure at the bottom of the water is 2500 Pa. Then additional air is pumped in, increasing the pressure of the air above the water by 1500 Pa. What...

622 kg * 9.8 = 6095.6 N 6095.6N / (1000 * 9.8) = 0.622 0.622 / 0.700 = 88.9% is this correct?