Recent content by mathguy2

Homework Statement A cargo packed for aerial dropping can withstand an impact speed of 20 mph. A 100 foot diameter circular parachute is used for a particular load. What is the largest load (including the chute itself) that can be accommodated by this chute. [/B] Homework Equations Vt =...

Ugh, Ok so doing it symbolically, where L = D for (Distance from main wheels to nose wheel) I get... L1 = (D x 948) / 1350 L2 = (D x 402) / 1350 but to where from here?

So there's no way to get a non-symbolic answer?

Thank you for the input. Would you mind taking a look at the more advanced center of gravity problem I posted. It's really frustrating me at the moment.

Homework Statement A Cessna C-172M has empty weight 1350 lbs. When it is weighed, the load on each of the main wheels is 474 lbs. The load on the nose wheel is 402 lbs. Where is the center of gravity of the empty Cessna? Ok so the question assumes you know what a Cessna looks like, but it's...

Homework Statement A partially loaded plane weighs 115,000 pounds. A famous actor's steamer trunk, weighing 300 pounds, is put into the rear cargo hold 250 inches behind the center of gravity. How much does this extra hold shift the center of gravity. Homework Equations W1 = W x (L2 / L) W2...

I just wanted another pair of eyes of this because I'm uncomfortable with these problems at the moment (it's a new concept). Many thanks. Am I correct?

Homework Statement Bearers at the front of a 9 zereth litter sense that they are carrying a 200 mina load. Those at the rear sense that they are carrying a 250 mina load. How large is the total load on the litter and where is the single equivalent litter load placed. (Drawing)...

I appreciate the replies very much, though, because I would've sat here and squinted at this problem for a few hours (I wish that were hyperbole, but it isn't).

It seems too remedial, but when working through all three plug and chug solutions, the numbers seem to be accurate representations of what would likely occur. I think you're all correct, though. The wording of the problem is just ambiguous to a certain extent, and I think it lends itself to...

So then for: "If the racket is moving at 60 mph, how fast does the ball come off the racket?" Vball = ε × Vracket Vball = ε × 60 Vball = 1.5 x 60 Vball = 90mph if the racket moves at 60mph?

But if they're the same why are there different values ? That's the problem exactly as it's written, and I agree, it makes no sense. Perhaps this information: "The United States Tennis Association imposes a rule on ball manufacturers: σ = 1.5" is a red herring? Cruel, but possible?

Homework Statement A player swinging a tennis racket comprises a very heavy flat object (the racket-arm body combination) which makes a head-on collision with a very light object (the 2 ounce ball). The ball leaves the racket according to the formula: Vball = ε × Vracket The United States...

oh right, inches cubed?

Oh, wow. So the volume of that box would be: Length times Width times Height of the box? 48inches x 96inches x 3inches = 13824? 13824 is the volume of air that is swept out during this motion?