Balancing weights (simpler version)

[mathguy2]

Homework Statement

Bearers at the front of a 9 zereth litter sense that they are carrying a 200 mina load. Those at the rear sense that they are carrying a 250 mina load. How large is the total load on the litter and where is the single equivalent litter load placed.

(Drawing)

I---------------------------------------------------I (plank)

200 hangs from the left side. 250 hangs from the right

Homework Equations

L₁ = (L x W₂) / W

L₂ = (L x W₁) / W

The Attempt at a Solution

Ok so W = 200+250 = 450 (total load). & L = 9 (given)[/B]

L₁ = (9 x 250) / 450 = 5

L₂ = (9 x 200) / 450 = 4

So this means the weight is hanging 5/9s of the way from the left side of the plank.

 

[mathguy2]

I just wanted another pair of eyes of this because I'm uncomfortable with these problems at the moment (it's a new concept). Many thanks. Am I correct?