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Balancing weights (simpler version)

  1. Feb 26, 2015 #1
    1. The problem statement, all variables and given/known data
    Bearers at the front of a 9 zereth litter sense that they are carrying a 200 mina load. Those at the rear sense that they are carrying a 250 mina load. How large is the total load on the litter and where is the single equivalent litter load placed.


    I---------------------------------------------------I (plank)

    200 hangs from the left side. 250 hangs from the right

    2. Relevant equations
    L1 = (L x W2) / W

    L2 = (L x W1) / W

    3. The attempt at a solution

    Ok so W = 200+250 = 450 (total load). & L = 9 (given)

    L1 = (9 x 250) / 450 = 5

    L2 = (9 x 200) / 450 = 4

    So this means the weight is hanging 5/9s of the way from the left side of the plank.
  2. jcsd
  3. Feb 26, 2015 #2
    I just wanted another pair of eyes of this because I'm uncomfortable with these problems at the moment (it's a new concept). Many thanks. Am I correct?
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