Recent content by mdawg467

  1. M

    Need help understanding this thermo. derivation

    Thanks dude, I was getting lost with the notation as well. This helps out big time.. Not sure what the book was doing lol.
  2. M

    Thermodynamics: Piston and Cylinder

    Success! I did it your way and I got the same result!
  3. M

    Thermodynamics: Piston and Cylinder

    Thanks Chet once again! I'll check to see if this way produces the same answer I got above in the edited post I made..
  4. M

    Thermodynamics: Piston and Cylinder

    Awesome, thanks Chet! Okay, I am getting a little confused here, but here is what I have: Vi=4.798m3 (using the ideal gas law I got 4.927m3) Vf= (0.10)(Vi)=0.4798m3 Specific Volume of the saturated vapor is 0.3928 m3/kg Specific Volume of the saturated liquid is 0.0010191 m3/kg...
  5. M

    Need help understanding this thermo. derivation

    Im trying to understand this concept of deriving an expression for (\frac{\partial T}{\partial P})s in terms of T, V, Cp, \alpha, and \kappaT (\frac{\partial T}{\partial P})s is evaluated by measuring the temperature change and the specific volume change accompanying a small pressure change...
  6. M

    Thermodynamics: Piston and Cylinder

    well, once we reach 0.47 MPa we are dealing with a saturated steam now..which means that there must be an equilibrium between the liquid that forms (very little) and the vapor correct? According to my steam table, the specific volume of liquid at 150 degrees C and 0.4758 MPa is 0.001091 m^3/kg...
  7. M

    Thermodynamics: Piston and Cylinder

    Thanks Chet! So, looking at the initial conditions of T=150 degrees C, and P=0.20 MPa I am looking at a superheated vapor..correct?
  8. M

    Thermodynamics: Piston and Cylinder

    Thank you so far for your time. That was the entire question given. Okay I understand about not being able to treat it as an ideal gas, hence the substitution I made using PV=RT is not valid, correct? So then, the work=-∫PdV=P(V2-V1) then? Would I be able to make an assumption that...
  9. M

    Thermodynamics: Piston and Cylinder

    Hm..I actually had a brain fart about that..Thanks! I'll treat it as an ideal gas then.. U2-U1=Q-∫PdV=Q-RT∫(1/V)dV=Q-RTln(V2-V1) ..hmm I am asked to find work and heat.. ..so I can find the work since W=-RTln(V2-V1) ..and the initial U1 is known since it is a function of temperature...
  10. M

    Thermodynamics: Piston and Cylinder

    Homework Statement A piston-and-cylinder device contains 5 kg of water initially at 150◦C and 0.20 MPa. The frictionless piston is then pushed slowly in an isothermal process until the volume of water becomes 10% of its initial value. Calculate the heat and work exchanged between the device...
  11. M

    Given the plane curve, find tangent vector

    Homework Statement Consider the plane curve \overrightarrow{r(t)}=e^tcost(t)\hat{i}+e^tsin(t) \hat{j} Find the following when t= ∏/2 Part A: \hat{T}(t) Part B: \hat{B}(t) Part C: \hat{N}(t) Homework Equations \hat{N}(t)=\frac{\hat{T}(t)}{||\hat{T}(t)||}...
  12. M

    Find mag. of net electric field at the center

    Homework Statement A point charge is placed at each corner of a square with side length a . The charges all have the same magnitude . Two of the charges are positive and two are negative, as shown in the following figure. my figure: (image each charge represents a corner of the square)...
  13. M

    How Do You Calculate Frictional Force on a Block?

    Thank you! Yeah only here in America haha..
  14. M

    How Do You Calculate Frictional Force on a Block?

    Homework Statement A 3-lb horizontal force is applied to a 10-lb block on a rough horizontal surface. The block is initially at rest. If \mus is 0.5 and the \muk is 0.4, the frictional force on the block is? Homework Equations FN=mg Fk=\mukFN Fs,max=\musFN The Attempt at a...
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