Recent content by mdub12

never mind, pretty sure it has to be all calculated by hand

you don't need to already be really good in math to be an engineer, it's just going to be a lot harder. you can learn anything if you put enough time and effort into it. but as for being an engineering major, any type of engineering is going to be the hardest of majors compared to any other...

is there a simple way to determine the section modulus of a member made of a W and WT shape welded together, one on top of another about the x-axis. the steel manual has the properties for the individual sections; would the section modulus of each be able to be added together or will i have to...

do A level classes count for credit in college? if so, take the english so you won't have to take it in college.. your going to want to take chemistry in college, so you have a good understanding of it when you need to use it in more advanced classes

i don't think he has given you any assignment yet, he's just telling you what your going to be doing

I figured it out.. AD = Adm + kD AD = 0 K11 = EA/L + (EA/(L+e))cos2(30) + EA/L cos2(60) = 2EA/L Adm = PL/EA = ecos(30) --> P = EAe√3/2L --> D = √3e/4 AR1 = Arm + FrD AR1 = EA√3e/4L AR2 = -5EAe/8L AR3 = EA√3e/8L

your reactions at A and B are miscalculated I get 23.333 at A and 18.667 at B

http://www.flickr.com/photos/53948823@N08/6193375731/ I need to solve this problem but with member 2 as L+e instead of L, and omit the load.. Since I only see one degree of freedom, i don't know how to set up the matrix to solve for the 3 forces. I have K11 = EA/L + (EA/(L+e))cos2(30) +...