Recent content by menglish20

  1. M

    Calculating free-fall acceleration of other planets

    I had a guess that mass isn't needed but I couldn't figure out a way to calculate acceleration without it. Am I overthinking this? Given velocity and orbit radius, could you use: Fc= m*ac, so ac=v2/r ? If so, this is way easier than I thought. Edit: I don't think this is correct. First, I...
  2. M

    Calculating free-fall acceleration of other planets

    Homework Statement Here is the text of the question: "A satellite circles planet Roton every 2.8 h in an orbit having a radius of 1.2 X 10^7 m. If the radius of Roton is 5.0 X 10^6 m, what is the magnitude of the free-fall acceleration on the surface of Roton?" Homework Equations...
  3. M

    Oscillatory Motion - Determining equation of motion

    Homework Statement A particle with a mass of 0.5 kg is attached to a horizontal spring with a force constant of 50 N/m. At the moment t = 0, the particle has a maximum speed of 20 m/s and is moving to the left. (a) Determine the particle's equation of motion. (b) Where in the motion is the...
  4. M

    What Determines the Peak Angular Speed of a Rotating Cylinder?

    v=rw So, I'd take .5 * 3.47 = 1.74 m/s. Then for part d, θ = 6.43, so the number of rotations would be 1.02. All these answers match the given solutions, thanks for clarifying this problem!
  5. M

    What Determines the Peak Angular Speed of a Rotating Cylinder?

    Glad to be here :smile: Right so the derivative would be ω=5t - 1.8t2 So I solve for that set to zero, and i get t = 0, 2.78. So I know the time where the velocity peaks is between those times. I'm going to guess that it acts parabolic, so the peak must be the midpoint, so t=1.389 s...
  6. M

    What Determines the Peak Angular Speed of a Rotating Cylinder?

    Homework Statement In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller is 1.00 m, and, while being driven into rotation around a fixed axis, its angular position is expressed as θ =2.50t2 - 0.600t3 where θ is in...
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