Calculating free-fall acceleration of other planets

AI Thread Summary
To calculate the free-fall acceleration on the surface of planet Roton, the orbital radius and velocity of the satellite are crucial. The satellite's velocity was determined to be approximately 7479.98 m/s based on its orbital period and radius. The correct approach involves using the formula a = v^2/R, where R is the radius of Roton, rather than calculating mass, which is unnecessary for this specific calculation. The discussion highlights the simplification that arises when using the orbital velocity directly to find acceleration. Ultimately, the free-fall acceleration on Roton can be calculated without needing to determine its mass.
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Homework Statement



Here is the text of the question:
"A satellite circles planet Roton every 2.8 h in an orbit having a radius of 1.2 X 10^7 m. If the radius of Roton is 5.0 X 10^6 m, what is the magnitude of the free-fall acceleration on the surface of Roton?"


Homework Equations



v=d/t

M= [(Ve)^2*R]/(2G)

a=GM/r^2

The Attempt at a Solution



This is presented as multiple choice, and I've been able to find the answer as 27 m/s^2 but I haven't been able to figure it out on my own.

What I tried to do is find the mass of Roton using the orbit speed.
I took the distance traveled by the satellite, 2*pi*1.2e7, and diving it by the time of one complete orbit, 2.8 hr or 10080 s. I calculated this velocity as 7479.98 m/s.

To find mass, I used the second formula I listed, and used the radius of Roton as R. I'm not sure if this is correct. I used this mass in the third formula, using the sum of Roton's radius plus the orbit radius. I think this may also be incorrect. I got an answer that was significantly different than the multiple choice answers provided. Can someone steer me in the right direction?
 
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To find mass, I used the second formula I listed, and used the radius of Roton as R. I'm not sure if this is correct.
No, it's not correct. The orbital radius should have been used as R.
I used this mass in the third formula, using the sum of Roton's radius plus the orbit radius. I think this may also be incorrect.
Indeed. You should have used just Roton's radius.
 
If you know the velocity and the orbit radius you can find the acceleration, no need for mass
 
Zula110100100 said:
If you know the velocity and the orbit radius you can find the acceleration, no need for mass

I had a guess that mass isn't needed but I couldn't figure out a way to calculate acceleration without it. Am I overthinking this? Given velocity and orbit radius, could you use:

Fc= m*ac, so ac=v2/r ?

If so, this is way easier than I thought.

Edit: I don't think this is correct. First, I don't even know if that equation is true, and if so, the ac would not be the free-fall acceleration, but the centripetal acceleration that maintains the satellite in a circular path.

Edit 2: I've figured it out! You do indeed need mass. Calculate it using v=sqrt(GM/R). Then use the mass in the formula a=GM/R^2. The R in the first equation is the orbital radius and the R in the second is the radius of Roton. This may have been what Barakn was explaining but I was using the wrong formula for calculating the mass. Thanks for the help, Barakn and Zula!
 
Last edited:
You can calculate the mass, but it's not necessary. We know that M= Ve2*R/G (you typed out the formula wrong) and a = GM/r2. Substitute M into the second equation to get a = G * Ve2*R/(r2*G) = Ve2*R/r2. Everything performed in one calculation in which G and M have magically disappeared.
 
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