Recent content by Mitch1

Your thermal conductivity is given in kW m-1 k-1 this will give your answer x10-3 kW m-2 k-2 which when you covert to W you get your answer

Yes that looks correct but there needs to be a power of 0.25 at the end of your equation

Try working out the nusselt number with the values given and 0.915 you worked out. Once you have nu you can then put this into the heat transfer coefficient equation

I am not sure what you are trying to do? Your 0.915 is essentially Pr but you can just plug the values into the equation you quoted in post #18

Yes you are correct on both counts

Hi I will dig out my notes and let you know. I am not 100% off the top of my head Regards

The air isn't coming from the vents it is being extracted there. The air is coming from above the surface being blown downwards

Thanks for this guidance - much appreciated I will look into this as it is a practical problem Thanks again

Is that not for just jets onto a heated surface? Rather than air? Thanks again

Thanks, rough sketch shows the air being forced into surface, this will create turbulent flow? But can't find anything on how to approach this and it is both linear and turbulent to some extent Thanks

Hi Nidum, thanks for your reply - yes I can attach a sketch although I am not too sure how to do it on this forum - any ideas? (Apologies)

Hi All, I have a situation were I need to evaluate the heat transfer coefficient of a horizontal surface. The surface has tubes within although I first used "flow across a bank of tubes", this has been untrue due to the air flow coming from above the surface flowing vertically (and...

No problem cheers

No problem, do u think that is on the right lines or way off?

Sorry yes there you go