I tried googling the problem and someone else had a similar problem. They got 6.00 for acceleration and I'm not too sure as to how the person got it, but I used it and got 19.5 for the first question.
I don't know how to calculate the new velocity after 4 seconds though.
I used
vx = v0 + axt...
can someone please clarify this to me? I have a problem very similar to this one.
what exactly are you integrating and what do you get once you integrate?
where s is seconds, I'm assuming?
so v^2 = 0 + 2*(2.293m/s^2)(0.377m/s?)
I got time by dividing 2.76 by 1.04 since d = speed * time
square root each side and I get v = 1.314556188
the answer was 2.19 :x...probably did something wrong.
I got the answer after dividing by 1.04. I don't know why that happened to be the answer nor do I know why that was a necessary step. Someone please explain?
so the string can handle 2.587 times the force it's handling right now right? but how do I incorporate that into an equation to find speed or acceleration?
Homework Statement
A 2.45×10^4-kg rocket blasts off vertically from the Earth's surface with a constant acceleration. During the motion considered in the problem, assume that remains constant. Inside the rocket, a 13.1-N instrument hangs from a wire that can support a maximum tension of...
How to calculate distance when there's a changing force?D:
Homework Statement
A 3.50kg box is moving to the right with speed 10.0m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F(t) =...
Homework Statement
A 8.00kg block of ice, released from rest at the top of a 1.04m--long frictionless ramp, slides downhill, reaching a speed of 2.76m/s at the bottom.
What is the angle between the ramp and the horizontal?
This I calculated as 21.9 degrees
What would be the speed of the ice...