Recent content by moy13

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    Gravitational potential and kinetic energy

    oh wow, that does make sense, thank you LowlyPion.
  2. M

    Gravitational potential and kinetic energy

    mv^2 / r = mg, then v^2 = rg where r = R so I get mgh = mg(2R) + (1/2)mRg mg cancels out and h = 2R + (1/2)R = (5/2)R is this correct? I don't really understand. Thanks for any help though.
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    Gravitational potential and kinetic energy

    Homework Statement A car in an amusement park ride rolls without friction around the track shown in the figure http://session.masteringphysics.com/problemAsset/1041727/8/YF-07-32.jpg It starts from rest at point A at a height h above the bottom of the loop. Treat the car as a particle...
  4. M

    Calculating the Force Required to Move a Crate at Constant Velocity

    I tried keeping n as the mass times gravity, but I get the wrong answer since there is a downward force exerted on the crate by the factory worker.
  5. M

    Calculating the Force Required to Move a Crate at Constant Velocity

    Homework Statement A factory worker pushes a 28.4 kg crate a distance of 4.6 m along a level floor at constant velocity by pushing downward at an angle of 31 degrees below the horizontal. The coefficient of kinetic friction between the crate and floor is 0.25. What magnitude of force (Fpush)...
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    Glide Distance of Piper Warrior w/ Engine Shut Off

    Would that be the thrust of the engine? But after the engine shuts off there is no more thrust right?
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    Glide Distance of Piper Warrior w/ Engine Shut Off

    so, could I use the law of cosines c^2 = a^2 + b^2 - 2ab cos(gamma), where c = L - W, a = L, b = -W, and gamma is the angle between L and W?
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    Glide Distance of Piper Warrior w/ Engine Shut Off

    Homework Statement When an airplane is in flight with the engine running, it is acted on by four forces. These are: (i) The weight of the airplane. (ii) The thrust provided by the engine, which pulls the airplane forward in the direction it is moving. (iii) The drag (air resistance), which...
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    Finding the height of a building

    Saw that 1.3 too, but I changed it to 1.2 and it's still wrong. Maybe I'm not understanding the concept. How do I solve for T? Is it T = sqrt( 2h/g )? and v(1/4) = g * ( sqrt( 2h/g - 1.2 )? then solve for h. It's what I did, but I got 254m which is wrong.
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    Finding the height of a building

    I tried solving for T but I still got a wrong answer for h
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    Height of a rocket at a certain time

    wow! Thank you so much LowlyPion. I did not notice how there were more than one time intervals.
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    Height of a rocket at a certain time

    Homework Statement During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upward at a steady 3.20 m/s^2. When it is 260 m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is...
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    Finding the height of a building

    Homework Statement Spiderman steps from the top of a tall building. He falls freely from rest to the ground a distance of h. He falls a distance of h/4 in the last interval of time of 1.2 s of his fall. What is the height h of the building? The acceleration is constant -g. Homework...
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