Recent content by myk127

oops. I forgot to multiply it by the displacement. so my solution would be: (a) -0.30*(3.50*9.8*sin 15)(3.40) = Wfk (b) Wg = (3.50*9.8*cos 15)(3.40) = Wg (c) 3.5*9.8*sin 15(3.40) = Wn (d) Wfk + Wg + Wn = Wt (e) ? am I right with my solutions now? how do I find (e)?

Homework Statement A 3.50 kg block slides 3.40 m down a long 15 degrees inclines ramp. the coefficient of friction between the block and the ramp is 0.30. find the following: (a) the work done on the block by friction (b) the work done on the block by gravity (c) the work done on the block by...

wow, thanks I never thought of that. part (a) was really my problem.

what would be my Δh then?

the values I used are: PEe - spring potential energy k - spring constant x - length of elongation or compression mgh - mass, gravity and height. sorry if i didn't understand, I'm kind of not good with physics. how come there's still ½mv² in the equation?

Homework Statement A 2.0 kg block is placed on top of a spring which is compressed 0.5 m. The spring constant of the spring is 2.50 N/cm. when the block is released, find (a) the velocity at which the block leaves the spring (b) the velocity of the block when it has risen 1.00 m (c) the...

you won't subtract it. you just have to divide the other side by the long equation you said.

you should group all the terms that has dy/dx in it on the other side. then factor out dy/dx.

ah. thanks for that. what about the F3? you don't have to multiply it to sin 30 becase it's parallel to the inclined right? so it's like rotating the figure by 30°.

Homework Statement A block moves up a 30° incline under the action of certain forces, three of which are as follows: F1 is horizontal and magnitude 40N. F2 is normal to the plane and of magnitude 20N. F3 is parallel to the plane and of magnitude 30N. Determine the work done by each force as...