What is Q?
N electrons * Charge of electron?
I'm going back and re-reading the entire chapter leading up to this one in cased I missed something.
I'm completely lost when it comes to electricity and that's not like me.
And now I end up with
Q=(Epsilon*E*Q) / eta
that makes no sense because if I go any further the Q's will cancel out *sigh*.. so I know I did something wrong.
Back to the drawing board.
Well I have another equation I was solving for earlier.
r = sqrt(Q/pi*eta)
I suppose I could substitute that into the equation set equal to Q and solve for Q.
Then maybe I could plug that Q from Q=Epsilon*A*E into the r = sqrt(Q/pi*eta) equation to find r.
Hmm. I can't stand...
I'm doing the same problem.
All I can find from the second equation is that Q = Epsilon * A * E
Which doesn't really help because even if I break down A into pi * r^2 I still don't know r.. because if I knew r I would know d, which is what we're looking for.
I don't get how that helps.
Homework Statement
The graph shows the net external force component F cos θ along the displacement as a function of the magnitude of the displacement s. The graph applies to a 65 kg ice skater.
http://img9.imageshack.us/img9/3441/0671.gif (a) How much work does the net force component do on...
Tried.
a) Use the equation Δx=1/2(Vo+V)t, so t=(2Δx)/(Vo+V)
From.
http://qaboard.cramster.com/physics-topic-5-218055-cpi0.aspx
Got 0.0003seconds, didn't accept it.
Also read all of
https://www.physicsforums.com/showthread.php?t=200285
He seems to think the part I think is hard is...
My problem is finding the time, the Δp (momentum) is a joke to find.
0.001seconds doesn't seem like a bad impulse time, considering the average of the problems I've been working with is 0.005 seconds, but it won't accept it, I'm not sure what else to do even since I've posted this because no...
I know this is an old message but this poster states he solved the problem by finding.
(simply restating correct solution posted in quotes here)
A=area
A=.5(Fmax)Δt
A=mv1-mv2
I think? I don't understand what equations the poster was trying to write out.
Wouldn't the change in...
I solved it, idk what the guy on the yahoo answers was smoking...
Although his idea on the velocities being additive did help me realize something about the momentum.
Consider this thread, closed.
[FONT="Comic Sans MS"][SIZE="5"]SOLVED
Homework Statement
Let me start by saying my ONLY question is. Why can I not use..
vf=(2aΔs).5
Why do I have to use
vf=(2mgH).5
to get the vf? Why have things changed now that I am dealing with momentum problems, isn't vf just vf...
Homework Statement
In a ballistics test, a 25 g bullet traveling horizontally at 1200 m/s goes through a 35 cm thick 350 kg stationary target and emerges with a speed of 850 m/s. The target is free to slide on a smooth horizontal surface.
(a) How long is the bullet in the target...
Hmm. From the way you word things it seems like you cannot check this answer online.. I have a bad track record with these types of problems as recently as last week, but I will try to give some input.
First of all, consider the direction of each acceleration. Are both acceleration in the...
I believe you pointed that out earlier in the problem that I had messed up the signs with my acceleration. Then it appears I did it again in the same problem, doh!