Bullet Enters/Exits Mass, Mass Slides

  • Thread starter Thread starter myxomatosii
  • Start date Start date
  • Tags Tags
    Bullet Mass
AI Thread Summary
The discussion revolves around a ballistics problem involving a bullet passing through a target. Participants express frustration over unclear equations provided by the professor, complicating their attempts to solve for the time the bullet spends in the target and the average force exerted. The key equations discussed include momentum conservation and kinematic equations to find time and deceleration. There is confusion regarding the calculation of time, with participants sharing their attempts and recalculations. The thread highlights the challenges of applying mechanics to complex problems and the need for clearer instructional materials.
myxomatosii
Messages
80
Reaction score
0

Homework Statement



In a ballistics test, a 25 g bullet traveling horizontally at 1200 m/s goes through a 35 cm thick 350 kg stationary target and emerges with a speed of 850 m/s. The target is free to slide on a smooth horizontal surface.

(a) How long is the bullet in the target?

(b)What average force does it exert on the target?

(c) What is the target's speed just after the bullet emerges?

Homework Equations



It would be nice to have some more equations, my professor gave the class four pages of equations scribbled in his horrible hand-writing, to help us... I guess. Instead of giving us the basic equations that we can use to plug-in to create our own equations he already solved them all out into the forms he understands, which means we have to un-solve them to try to make sense of them, so really I have no idea what other equations to put here since he has no clear division between which equations go with which section of the book.

momentum of system before = momentum of system after ||| Pi=Pf

The Attempt at a Solution



I already solved part C using the equation provided.

Part A I attempted something that I knew wouldn't work but gave it a try anyway and I know I need part A to solve B so I haven't gotten around to trying to solve B yet.

I seem not to be able to resist applying simple mechanics to complex problems just to see if I can knock it out of the way. Anyway I did this to solve for B, it was obviously going to be wrong but I submitted it anyway.

B: I tried to say that the

DT=0.35m

Vavg/DT=? Then that gave me seconds so I took s-1. Yea, it obviously was just bs, but that is how lost I am.
 
Physics news on Phys.org
LowlyPion said:
Here are some kinematic equations anyway.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2

As for determining the force, recognize that Δ in momentum divided by the Δt should give you your average force.

Thanks, getting to work on things now. Hopefully I can make some progress without having to ask too much here.
 
LowlyPion said:
Here are some kinematic equations anyway.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2

As for determining the force, recognize that Δ in momentum divided by the Δt should give you your average force.

My problem is finding the time, the Δp (momentum) is a joke to find.

0.001seconds doesn't seem like a bad impulse time, considering the average of the problems I've been working with is 0.005 seconds, but it won't accept it, I'm not sure what else to do even since I've posted this because no one mentioned time.

I'm given it decelerates from 1200m/s to 850m/s in the distance of 0.35m.

Finding the time should be cut and dry like I found it, but its not, so I'm confused.
 
Tried.

a) Use the equation Δx=1/2(Vo+V)t, so t=(2Δx)/(Vo+V)

From.

http://qaboard.cramster.com/physics-topic-5-218055-cpi0.aspx

Got 0.0003seconds, didn't accept it.
Also read all of

https://www.physicsforums.com/showthread.php?t=200285

He seems to think the part I think is hard is elementary =(

So I learned nothing from that as well.

I recalculated the time he declared to be right using the formula I tried using on mine(the same one I tried right above this in this very post), it gave his same answer. Meaning I am calculating time right, assuming he was, and he did get the right answer. Anyway, I am getting really annoyed with my "online" system when I am almost positive my answer is correct.. am I wrong?
 
Last edited by a moderator:
Start with determining the deceleration through the material.

That you can get from Vf2 = Vi2 - 2*a*x

In your case that would be 12002 - 8502 = 2*.35*a

Now armed with a you can determine t, from x = 1/2*a*t2

That arrives at a number a bit larger than .0003 sec.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top