Recent content by nil1996

You have to consider the tension on both sides of the element along the tangential direction!

The force due to the right liquid comes out to be 3/2*rho*g*R^2*l (from integration).So we can see the pressure = 3/2*rho*g*R and area = R*l. so i think we can conclude that surface to be a cuboid of dimensions R*R*l

If you try to change the surface you still have to find the relation between the force on curved surface and any other surface.So I think there is no way without integration.

sorry but i am not getting what you saying?Can you please explain a little.

o,made silly mistakes. \frac{dv}{dt}=\frac{k}{m}(\frac{D}{sinθ}-D)cosθ + g now what to do after this?Should we consider a small change in θ and integrate it over the "θ" range to find the velocity??

So i should write it as: F=k(D/sinθ -3) ... D =horizontal distance so putting this value in first equation: ma=Fcosθ + mg ma=k(D/sinθ-3)cosθ + mg dv/dt = k/m(D/sinθ-3)cosθ + g \frac{dv}{dt}=\frac{k}{m}(\frac{D}{sinθ}-3)+g

thanks for the reply Haruspex:smile: From hooks law: F=k*x ...where x is the length of spring. from geometry: cosθ=h/x so x=h/cosθ so F=k*h/cosθ

Homework Statement A ring is moving on a vertical rod attached to a spring. Find the velocity of the ring when spring becomes horizontal. The spring is ideal with spring constant 400N/m. Mass of ring is 10kg. Natural length of spring is 4m. Initially the ring is at rest as shown in...

O,thanks a lot :smile:

Homework Statement Here is a cube of resistors with each resistance of value "R".Find the equivalent resistance between A and B. Homework Equations The Attempt at a Solution My book says the equivalent circuit of the cube is : But i don't think it is correct.They have made parallel...

That's an interesting solution:biggrin:

i think using conservation of angular momentum will get me the answer.right?

So how do we calculate how much energy was useful from that collision?

Homework Statement A rod of length L and mass M is pivoted at the center C such that it can freely rotate in vertical plane.Initially the rod is at horizontal position.A blob of wax of mass M falls vertically with speed V and sticks to the rod midway between center and one end.If the rod...

thanks:smile: