Recent content by no_math_plz

I think collapse is related to which observation you are doing. So, the choice of basis is related at this observation (uniquely, if observable doesn't degenerate), and wavefunction, to respect this basis, collapses EVER.

That's true in vacuum, where is exactly c. Phase velocity in a medium has no meaning, I think; I've seen some cases where phase velocity is greater than c.

for a particle in a box I have more solutions (twice) because I ignore boundary conditions for first derivative! I must take account of these conditions because a Bloch electron can't be localized, is a running electron. I can't say "electron is in a volume V", I think it has no sense. So...

Ashcroft "Solid State Physics" p. 39

That's not true at equilibrium. n will increase initially, but after a few moments some electrons added will fall in valence band, reducing holes concentration. mass action law rules matter flow between two (classical) systems at equilibrium

I can't understand this conditions, and in general every boundary conditions for problems like this. they states "the choice of boundary conditions can be determined by mathematical convenience (!?) ... for if the metal is sufficiently large, we should expect its bulk properties not to be...

yes, addensate=to make more dense! sorry, I thought this word exist in English. I'm referring to an infinitely wide well, not necessarily infinitely deep one: this should represent the free space. the question is: why energies in this case aren't distributed uniformly? for example, in a...

right, but in an infinite well such series becomes a continuous energy density because energy levels addensate: try to imagine...

it's possible to have a current to compensate for the difference in generation and recombination rates, sure, but for a single kind of carrier. in stationary state, electron and holes currents give a total current whithout net flux, so NET recombination rates for electrons and NET recombination...

this is due to the fact that the input of the open-loop amplifier is very low, almost zero (this is the role of the high gain open-loop chain!). imagine this is not the case, in stationary conditions: then, the output will be so big to suppress the input signal, when reapplied to the input...

hi, I'm new on this forum, and I don't know english very well (sorry). maybe you can clarify me about this doubt. an electron in a well with infinite walls has a discrete set of energies, right? but if the length of the well is infinite, what can I say about energy state density? is it uniform...