Recent content by Not a Wrench

I know, thank you for the hint.

Those are the products in the equilibrium. But I figured it out, anyways. I was dividing by 5L of water when I should have been multiplying by 5L because I needed to eliminate that 5L in the denominator and get moles by itself!

The Kc equation contains (Ba2+ )(CO32- ) and they both gain x per the ice chart so therefore Kc = x2

Yeah, all I did was calculate 5.7E-6 = x2 and solved for x which got me to .002387. Isn't its units M/5L because the container contains 5L of water?

Then what is x supposed to be? I was under the impression that the number by which it BaCO3 decreases is equal to the x that each of the products increases by.

I forgot to add my last step but I know. It's the moles per liter. If I divide by 5 it gives me .000477 moles which is also not correct.

Homework Statement Excess BaCO3 is placed in a container containing 5L of pure water. Given the following info: BaCO3 (s) ↔ Ba2+ + CO3 2- and Kc = 5.7E-6 how many moles of BaCO3 dissolve? Homework Equations Kc=(Ba2+ )(CO3 2- ) = 5.7E-6 The Attempt at a Solution solved for x to get .002387...

Homework Statement Problem 132 Homework Equations Not sure. I know we will use Kc=[Products]/[Reactants] The Attempt at a Solution I tried to devise a balanced equation to use: AuCl (s) + NaCl (s) + H2O (l) → Au+ + 2Cl- + Na+ and then try solving from there

What I did in part A was divide 7.8E-4 by 3. However I am unsure what this is fundamentally doing apparently as I can not understand how to get part B. Do I divide 7.8E-4 by 2?

Homework Statement Homework Equations Δ[A]/aΔt = Δ[ B]/bΔt The Attempt at a Solution Δ[ I]/3Δt = Δ[H]/2Δt = 7.8E-4. What exactly am I supposed to do for this?

Homework Statement Suppose you were told you had a protein with molecular mass of 65,000 g/mol. Show how you would estimate the number of amino acids present in this protein. Keep in mind that you cannot calculate the exact number, the point of this is to approximate how many amino acids are...

There are 3CO2 molecules equaling 3(2*350) = 3(700). I reworked it again. Getting [8(410)+2(350)+5(498)] - [3(804)+4(2*460)] = -1672 kJ/mol. But that is also wrong and I only have one more chance to answer it. I'm positive I'm counting the number of bonds of one molecule incorrectly. Edit...

Homework Statement Calculate an approximate heat of combustion for propane (C3H8) in kilojoules per mole by using the bond dissociation energies in the table. (The strength of the O=O bond is 498 kJ/mol, and that of a C=O bond in CO2 is 804 kJ/mol.) Homework Equations C3H8 + 5O2 → 3CO2 + 4H2O...

Oh, it's conservation of ΔE? Now I see.

I never learned this during my lecture. Could you explain why this is?