I followed you advice but instead of calculating it I figured it would be better to simulate it in solidworks. I simulated a force of 5 N on the leg of the tool.
I got a maximum deflection of 10 mm, which I think is pretty big for such a small force
Bellow is the top view of the deflection
Thank you for your feedback.
The bending radius I am using is equal to the thickness of the material as that is what they use in the workshop.
I have some other questions in mind regarding this tool:
1) How long should the leg be relative to the base/web for maximum stiffness in the plane...
I would like to produce the 3mm thick sheet metal steel part shown bellow but I have a few questions.
I have my doubts about the whether the bending of the top right part (with the holes) will work. The 5 mm spacing has to be there as the tool will be inserted into a 3 mm surface
Feel free...
This is how the tool is connectec to the rail.
There is no load on it. The only requirement is that it's position along the rail should not exceed +- 5mm
Part one is connection the main frame via nuts and bolts
Part two has 4 teeth like structures that hangs onto the main frame
The only important direction is the one shown via the arrow.
Material is either sheet metal or aluminium.
no limitation on manufacturing techniques
Cost should be...
Hello everybody,
I am currently working on desinging a tool, and I would like to get your advice on how to increase it's stiffness.
The tool will be used for correct positioning of a component.
It consists of 2 parts :
And
It's not a homework questions, I am actually working with conveyor belts and need to calculate the speed the conveyor B based on time it takes for the parcel (hockey puck) to pass conveyor B. So this is real life problem not a homework.
With that said being said. Your second part suggesting...
I generalized the problem to get an approximate answer.
I removed the conveyor belt on the right and just assumed that the hockey puck has a speed of X when introduced on to the conveyor belt on the left
So U ( initial speed) = X
V ( final speed) = Y
S (distance) = 700
T (time...
Hello,
I am actually looking for a way to start as I am not sure how to approach it.
Here's what I have so far:
The question I believe lies at the point where the puck crosses from the first conevyor belt to the second.
I have this force diagram but I am not sure if it's right
(mentor note: moved here from a non-homework thread)
Hello
I am trying to find the time it will take for a parcel to pass over one conveyor belt
The conveyor on the right is Conveyor A The conveyor on the left is Conveyor B
they both have a length of 700mm
Conveyor A has a constant speed of...
The rods I was talking about ( going through D and E ) were not chosen based on calculations but based on avaibility at the time , hence I say that maybe smaller bars can be used.
You cleared up so much .
Thank you for all your help, it was much appreciated.
Yes that is why I prefer to keep 1 fixed pivot if possible. If not , then I will do the financials to see if it's feasible.
I'm now confused on what you mean, as that drawing isn't clear.( at the E' where 2 rods are connected)
Here's my drawing of your idea from your previous post
Moving D...
Now I understood what you mean. Very naive of me not to see it from the beginning
Let me first clarify the available possible space
As you can see in broadpic1 , the chute has two stands (feet) those are parallel to the ground.
As you can see in broadpic3 , we have 700 mm bellow the curved...