Ye, steady state makes more sense, sorry for my mis-wording. :P
m3a3 was of course a mistake - didn't notice it. :P Sorry, again.
If acceleration is constant, you can somewhat say it is "steady", at least theta would remain steady.
No, m2v2 is momentum, and m3v3 is momentum. I'm not mixing forces with momentum. You that equation to calculate (I believe) the speed (and acceleration) of block 3. (you might also need to add m1v1, as they are on the "static" side).
With vertical, I meant m1 being "vertical". :P Not the...
It took me a little while to understand how it would look like at t=0, but this does make sense.
You should have drawn it at t=0. :P Draw as it is draw, it suggest that theta(t) with t=0 isn't 0. :V
You need to create two equations, and solve them like that (unless you don't know how to, mathematically). And, yes, masses are important, because you need to calculate it using forces, but what you are really interested in here are accelerations.
You need to connect them, in one equation, so when you calculate a2 (from a1), you also connect it to possible theta from a3, because theta will affect your a1.
Find a2, by calculating the force that m1 will pull the line with.
(I assume no friction between m3 and m2 too) From momentum conservation, calculate a3. (m2v2 + m3a3 = 0 in any given moment)
Theta will be pretty much cosine of a1 (assuming it is vertical) and a3
It is far easier to understand simple Bohr model, than start with solving Schrödinger equation, don't you think?
And yes, it does explain electronic configuration. (electron energy levels)
I don't know for the others, but I learned how to not mistake them the "practical way".
Inclined plane was the best way for me to understand how this stuff works.
All you need to remember is that
sin(0)=0
sin(90deg)=1
cos(0)=1
cos(90deg)=0
And then certain inclinations of the plane. (for...
I have problem understanding what OP's problem is.
Wire is not source of voltage, no.
Also, there is no "voltage" in point. Voltage of a point is 0, because voltage is difference of electric potential.
On your 2), voltage between "a" and "b" will be 0 (assuming perfect wire, with no...
I'd say the energy here is crucial, which is in turn connected to speed - kinetic energy (hope I don't have to write it down).
Ever heard that bullet has "that-and-that kJ"? This is how sometimes destructive potential of a weapon is given.
It is true that the "force" that penny will be...
The reaction force IS the stress (somewhat... :D). For system to remain static, material needs to generate force equal to force applied to it, which is exactly stress.
And if you are asking why stress is generated - stress is resistance to outside force to break integrity of the material. You...
^ This is false.
You still have fluid in the pipe, which does increase the pressure, which can in turn, potentially, increase the fluid flow. You WILL get higher static pressure on the bottom using the H0-H2, because it is contained inside the tube, instead of being depressurized to the...