Recent content by phys_student1

Thank you!

Thanks, I would have liked a documented resource where I can see these discussions presented mathematically. BTW, I am not looking into any altitude above 100-200 meters.

I am looking for a book that teaches how to design an RC aircraft, given performance specifications: $$v_{stall}, v_{max}, m_{payload}, h_{max}$$ That is, given the stall speed, max. speed, payload and service ceiling, I'd like to know how to design the aircraft's air-frame (wing span...

But this blows up if cos(x)=0, although the original output would not!

Let: $$x_1=A\sin{\omega t}$$ $$x_2=\dot{x}_1=A\omega \cos{\omega t}$$ $$y=A\omega$$ We want to represent this system in a state space model. The state transition matrix read: $$A=\begin{bmatrix} 0 & 1 &\\ -\omega^2 & 0 \\ \end{bmatrix}$$ I am not sure what the output matrix will be like. Can we...

Thanks.

There must be something changed that causes them to have different occupancy. This thing should be the energy of each orbital. Do you agree with this interpretation?

"The presence of strain will lift that degeneracy, and one orbital will end up with a higher electronic occupancy (probability)" Does this mean the two orbitals will have different energy? This is what first come to my mind when I see "degeneracy lifting".

In this paper, the Orbital Polarization (OP) is defined as: $$OP=\frac{n_{x^2-y^2}-n_{z^2}}{n_{x^2-y^2}+n_{z^2}}$$ where $$n_i$$ is the occupancy of that given orbital. I would like to understand the physical meaning of this. Also, is there a difference between OP and Orbital Hybridization?

Cthugha, thank you! That was very clear. I agree that the connection to CTC is not really a rigorous one, which is why I was confused while reading the paper. P.S. I have (in my university) subscription to APS journals, but I prefer arXiv because some members don't have access.

Is the question not clear?

This paper experimentally simulates Closed Timelike Curves (CTC) through quantum optics experiment. Since I have no experience/background in this, I found it hard to understand how exactly the CTC is implemented in the circuit. [Note: I do understand QM, so no need to explain this].

Thanks for the reply. Actually, by "not difficult" I meant that it is possible. I said this because my first impression was that this is not for someone doing PhD in Physics. Of course the exam itself is difficult, I agree, but I mean that it is "doable", hopefully. I have the work...

Long story short: I have a B. Sc. in EE, and currently doing PhD in Experimental Condensed Matter Physics. I plan to go for industry. I found that it would not be difficult for me to pass the Electrical and Computer PE exam (both the "Computer Engineering" and the "Electrical and...

Well, C_D and C_L are Taylor expanded into many components which are usually obtained from a CFD software, so I am not sure.