Recent content by physics_fun
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X-ray diffraction; atomic form factor
Hey, I'm working on a problem about the atomic form factor. I found that the atomic form factor of an fcc lattice of Buckyballs (C60 atoms) looks like f~(sin(Gr))/G multiplied bij some constants. The question is now to explain from this atomic form factor why the (2,0,0) X-ray diffraction...- physics_fun
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- Atomic Diffraction Form X-ray X-ray diffraction
- Replies: 2
- Forum: Advanced Physics Homework Help
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Graduate Charge conservation in curved spacetime
:blushing: You're right, I didn't think of that!- physics_fun
- Post #9
- Forum: Special and General Relativity
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Graduate Charge conservation in curved spacetime
I think there is still a mistake, because 4 \pi \nabla_a j^a = \nabla_{[a} \nabla_{b]} F^{ab} = - \frac{1}{2} ( R_{abc}{}^{a} F^{cb} + R_{abc}{}^{b} F^{ac} ) = \frac{1}{2} (R_{bc} F^{cb} - R_{ac} F^{ac} ) = \frac{1}{2} (R_{bc} F^{cb} + R_{ac} F^{ca} ) so they don't cancel. Is there a...- physics_fun
- Post #6
- Forum: Special and General Relativity
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Graduate Charge conservation in curved spacetime
Thanks! I've spent almost the whole day on it, because I didn't know which way to go... Are you allowed to take only the asymmetric part of the covariant derivatives \nabla_{[a} \nabla_{b]} F^{ab} because the symmetric part gives zero in combination with the anti symmetric F tensor?- physics_fun
- Post #5
- Forum: Special and General Relativity
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Graduate Charge conservation in curved spacetime
For the case of ordinary erivatives that is true, because these derivatives commute. But I am looking for the proof in de case of covariant derivatives, and these don't necessarily commute...:(- physics_fun
- Post #3
- Forum: Special and General Relativity
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Graduate Charge conservation in curved spacetime
I'm reading some texts on general relativity and I am wondering how one can mathematically proof that the covariant derivative (wrt mu) of the four-vector j^mu equals zero. I know that the covarient derivative (wrt nu) of F^mu^nu equals the four-current times some costant and that you should...- physics_fun
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- Charge charge conservation Conservation Spacetime
- Replies: 17
- Forum: Special and General Relativity
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Graduate Calculate that the proton and neutron in a deuteron
Maybe I didn't formulate it very clear, but what I mean is this: http://www.shef.ac.uk/physics/teaching/phy303/303soltn1.html#sols2 (2nd solution) So in this calculation it is about 64% of the time the case. But I don't know why the deuteron doesn't dissociate...- physics_fun
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate Calculate that the proton and neutron in a deuteron
You can calculate that the proton and neutron in a deuteron spend quite some time so far away from each other, that they are outside each others force range. Why doesn't the deuteron break up? Is it because of the binding energy?- physics_fun
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- Deuteron Neutron Proton
- Replies: 3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate How do parities add up in a two-body system in the shell model?
Thanks!:smile:- physics_fun
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate How do parities add up in a two-body system in the shell model?
I'm confused about how parities 'add up'. (I'm using the shell model of a nucleus) If you have e.g.a neutron in a d state (so l=2) and one in a p state (l=1), what is the parity of the total system? Do you have to multiply (+1*-1=-1?) or add the l values or something completely different?- physics_fun
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- Body Parity System
- Replies: 3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate Feynmann diagrams, bhabha scattering
It's completely clear to me now! Thank you very much for your help!:smile::smile::smile:- physics_fun
- Post #16
- Forum: Quantum Physics
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Graduate Feynmann diagrams, bhabha scattering
small angle approximation:wink:- physics_fun
- Post #13
- Forum: Quantum Physics
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Graduate Feynmann diagrams, bhabha scattering
About the second: is it true that (threevectors:) if p2=0, p1=p3+p4 so (p1)^2=(p3)^2+(p4)^2+2(p3)(p4) now (p3)(p4)=0, so (p1)^2=(p3)^2+(p4)^2, and this can only be true if p4=0 or p3=0?- physics_fun
- Post #12
- Forum: Quantum Physics
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Graduate Feynmann diagrams, bhabha scattering
I'm understanding this one:cool:!- physics_fun
- Post #10
- Forum: Quantum Physics
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Graduate Feynmann diagrams, bhabha scattering
Ok, I think I'm getting it now: E1, E2, E3 are the rest-energies, p1, p3, p4 the three vectors (p2 is defined 0)- physics_fun
- Post #9
- Forum: Quantum Physics