How do parities add up in a two-body system in the shell model?

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SUMMARY

The discussion clarifies how parities are calculated in a two-body system using the shell model of a nucleus. Specifically, the parity for a state is defined as π = (-1)^{l}, where l represents the orbital angular momentum. For a neutron in a d state (l=2) and another in a p state (l=1), the total parity is determined by multiplying the individual parities, resulting in π_total = π₁ * π₂ = (-1)^{l₁ + l₂}. Therefore, the total parity for this system is -1.

PREREQUISITES
  • Understanding of the shell model in nuclear physics
  • Familiarity with orbital angular momentum (l) concepts
  • Knowledge of parity in quantum mechanics
  • Basic mathematical operations involving exponents
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  • Study the implications of parity in nuclear reactions
  • Explore the shell model's application in predicting nuclear structure
  • Learn about angular momentum coupling in quantum mechanics
  • Investigate the role of parity in particle physics
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Students and researchers in nuclear physics, particularly those studying the shell model and quantum mechanics, will benefit from this discussion.

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I'm confused about how parities 'add up'.
(I'm using the shell model of a nucleus)
If you have e.g.a neutron in a d state (so l=2) and one in a p state (l=1), what is the parity of the total system? Do you have to multiply (+1*-1=-1?) or add the l values or something completely different?
 
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Hey
The parity \pi for a state is (-1)^{l} The total parity is
\pi_{1}*\pi_{2} or
(-1)^{l_{1}+l_{2}}
 
Thanks!:smile:
 
Yes, parities are multiplied.
 

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