Recent content by PhysicsKT

I see. Makes perfect sense now. Thanks!

The energy density of an electromagnetic field with a linear dielectric is often expressed as . It is also known that energy can be found by . Using the latter, the energy density is found to be , as is well known. If you integrate the latter only over free charge and ignore bound charge, you...

Thanks. Got it! :biggrin:

But what we want is to minimise time, not distance.

Homework Statement A honeybee is flying parallel to tabletop at height with velocity .With its wings it can acquire a maximum acceleration of . At an instant when honeybee is vertically above honey drop on tabletop and decides to reach the honey drop. Neglect reaction time of honeybee and...

I think the boy has made the setup, fixed it, and now the ant will travel there. There is no such thing as changing ##y## now. I tried solving it, and I know how to. But I'm one equation less, and thus the equation keeps giving me ##1=1## back.

^True. That is a mistake. Continuing on what you mentioned, we find ##l_1, \text{and}, l_2##. This gives: $$t = \frac{r}{v} \cdot (\cos{y} +2\sin{y})$$. But I believe using trigonometry to set ##y## in terms of knowns should give the answer, since ##y## is not a variable. Anyone help me with...

If it does not mean going exactly straight down with ##2v## and straight up with ##v##, do you think it means going anywhere making an angle ##0 \leq \theta \leq 180## means going upward with ##v## and going anywhere making an angle ##180 \leq \theta \leq 360## means going downward with ##2v##...

But even then the answer is not matching with the correct answer. Then the answer would be ##t = \frac{l_1}{2v} + \frac{l_2}{v} = \frac{r\sqrt{2}}{2v} \cdot (3-\cos{2y})## This should give the minima at ##\cos{2y} = 1## or ##y = 0##. At this angle the answer should be ##\boxed{t =...

What is galilean transformation? I was able to do this problem easily using maxisimation of a function using differentiation. It's from I.E. Irodov.

Tip: Doing this in polar coordinates should help. After you've cart bashed it, try by polars too.

Here's the problem: https://i.stack.imgur.com/rUVvu.png What I did: [2]: https://i.stack.imgur.com/AX2Ye.png [3]: https://i.stack.imgur.com/K1Zbi.png To those who could not understand what I read: So basically I used some geometry to to get $l_1$ and $l_2$ in terms of $r$ and the assumed...

I'm not very comfortable using complex numbers- can you write down the whole solution?

I don't know, please guide me how to parameterise the motion.

OOPS sorry for the typo.