Recent content by physicslove22
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How much charge inside a Gaussian surface?
Ok so I've checked over this several times, and I plugged it into my calculator wrong, so Flux2 = 0.8. However, it is still wrong! Does anyone know if there's some trick to it that I'm missing?- physicslove22
- Post #7
- Forum: Introductory Physics Homework Help
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How much charge inside a Gaussian surface?
I think I may have found my mistake: wouldn't Flux2 = (.12) (.05) (400) cos (90 - (inverse sine (.04/.12)) = .01424 ? Then net flux would be -0.1458?- physicslove22
- Post #6
- Forum: Introductory Physics Homework Help
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How much charge inside a Gaussian surface?
Here is the figure!- physicslove22
- Post #3
- Forum: Introductory Physics Homework Help
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How much charge inside a Gaussian surface?
Homework Statement The electric field has been measured to be horizontal and to the right everywhere on the closed box shown in the figure. All over the left side of the box E1 = 80 V/m, and all over the right, slanting, side of the box E2 = 400 V/m. On the top the average field is E3 = 260...- physicslove22
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- Charge Electric flux Gaussian Gaussian surface Surface
- Replies: 10
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
Ohhhhh wow I can't believe I was looking at it that way... And I googled the force lines and the line is headed in the -y direction... thank you both for patiently guiding me to finding my stupid mistake! o0)- physicslove22
- Post #14
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
Hmm well we haven't done that in class yet, but I think I can do it... Am I correct in drawing my electric field line from the electron's location at <-3x10^-8, 48000, 0>?- physicslove22
- Post #11
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
Oh whoops! I meant negative electric field... So what about the x-axis value?- physicslove22
- Post #9
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
I'm thinking about the way I would draw my answer as a vector on a graph that includes the two charges... It doesn't make sense to me that that the force vector would be <0, -7.68x10^-15, 0> so that it extends downward on the y-axis directly below the charges, instead of extending downward...- physicslove22
- Post #8
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
Well an electron has a negative charge, so after being multiplied to a negative electric field, the force would be pointing in the positive direction.- physicslove22
- Post #6
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
Yes I did, and the electric field is pointing in the +y direction, and the force is pointing in the -y direction... Is that correct?- physicslove22
- Post #3
- Forum: Introductory Physics Homework Help
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Force on an electron due to a dipole?
Homework Statement A dipole is centered at the origin, and is composed of charged particles with charge +e and -e, separated by a distance 9 ✕ 10-10 m along the y axis. The +e charge is on the -y axis, and the -echarge is on the +y axis. An electron is located at <-3 ✕ 10^-8, 0, 0> m. What is...- physicslove22
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- Dipole Electron Force
- Replies: 14
- Forum: Introductory Physics Homework Help
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Photon energy of a certain material?
Oh! That makes a lot more sense now! Thanks for all your help!- physicslove22
- Post #19
- Forum: Introductory Physics Homework Help
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Photon energy of a certain material?
The only possibility I can see from this is that one of them would be 1.11, which doesn't fit the limits the problem gave us...- physicslove22
- Post #17
- Forum: Introductory Physics Homework Help
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Photon energy of a certain material?
Would it emit photons from N=3 to N=2, N=2 to N=1, and N=3 to N=1? So it would be .64 and .37eV?- physicslove22
- Post #10
- Forum: Introductory Physics Homework Help
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Photon energy of a certain material?
Oh... Also I just realized that -13.6/N^2 is only for hydrogen atoms, I will need to devise a different approach...- physicslove22
- Post #8
- Forum: Introductory Physics Homework Help