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## Homework Statement

A dipole is centered at the origin, and is composed of charged particles with charge +

*e*and -

*e*, separated by a distance 9 ✕ 10-10 m along the

*y*axis. The +

*e*charge is on the -

*y*axis, and the -

*e*charge is on the +

*y*axis.

An electron is located at <-3 ✕ 10^-8, 0, 0> m. What is the force on the electron, due to the dipole?

## Homework Equations

Electric field of perpendicular charge: (9*10^9)(2qs)/(d^3)

where q = source charge, s = distance between the dipole charges, d = distance to observed location

F = qE, q = observed charge

## The Attempt at a Solution

E = (9 x 10^9)(1.6 x 10^-19)(9 x 10^-10) / (3 x 10^-8)^3 = 48000

F = (-1.6 x 10^-19)(48000) = -7.68 x 10^-15

So in vector form, would this be <0, -7.68x10^-15, 0> ? I thought it would be <-3 x 10^-8, -7.68 x 10^-15, 0>, because the force vector would extend down from the observed location, but it turns out this is wrong... I'm semi-confident that the magnitude is correct...