A dipole is centered at the origin, and is composed of charged particles with charge +e and -e, separated by a distance 9 ✕ 10-10 m along the y axis. The +e charge is on the -y axis, and the -echarge is on the +y axis.
An electron is located at <-3 ✕ 10^-8, 0, 0> m. What is the force on the electron, due to the dipole?
Electric field of perpendicular charge: (9*10^9)(2qs)/(d^3)
where q = source charge, s = distance between the dipole charges, d = distance to observed location
F = qE, q = observed charge
The Attempt at a Solution
E = (9 x 10^9)(1.6 x 10^-19)(9 x 10^-10) / (3 x 10^-8)^3 = 48000
F = (-1.6 x 10^-19)(48000) = -7.68 x 10^-15
So in vector form, would this be <0, -7.68x10^-15, 0> ? I thought it would be <-3 x 10^-8, -7.68 x 10^-15, 0>, because the force vector would extend down from the observed location, but it turns out this is wrong... I'm semi-confident that the magnitude is correct...