Recent content by physicsvalk

(If my question seems irrational, it's ok - I'm an undergrad!) So I was reading up on the standard model and read that Z bosons are their own antiparticles. Does this mean that when two Z bosons are in physical contact, they annihilate? I ask this for photons too since I read this on the...

Ohh, I see. Thanks for the help!

The question itself is asking for the equation of motion in cartesian coordinates. My question is, how can I incorporate the rotation into my answer?

Right now we're working on nonlinear mechanics, but we've covered Lagrangian mechanics. I'm not sure how I should start this problem using either method. I know that the rotation will cause the bead to slide out, but I'm not sure how to model it...

I was correcting your language, not the physics. Yes there is an upward force, but it is not a net force. I never said the upward force was the net force.

The upward force is equal to the weight of the water displaced by the body, not the displaced body.

Work?

It seems like you're first finding the compliment of the angle before you're breaking down the vector. If you do this, note that you're looking at the opposite angle and then the sine/cosine convention would change. EDIT: Try solving the problem by leaving the angles (instead of finding the...

The magnitudes you already know; it's given to you. Force of gravity, as you said in the post before, has a strength of mg. Tension is twice that. So there's the magnitudes! The directions should be straightforward. Gravity is always acting toward the center of the planet. The tension is a...

When you say "[N20(degrees)E]" do you mean 20 degrees North of East?

A) Look at all of the forces acting on the ball at the top. There is more than tension. B) Your math looks correct. Just note that the net force on the ball at the top is actually ƩF = 3mg, not T= 3mg. It looks like your next line is right, but just make sure you have your terms correct.

It would be easier to have the full question.

Try looking here: Rotational Dynamics

For that, yes. Now you can simply apply the Lagrangian and get your answer :D

Starting from rest at a point O, let's call it, the motor supplies a torque so that by the second time we pass O, the angular speed is 3.49 rev/s. Based on this, you can use one of the kinematics equations (re-vamped into their respective rotational forms) and then incorporate the mass of the...