Recent content by PlatoDescartes

Capacitance is not dependent on voltage nor charge though, only material/geometry. Which is why it doesn't change.

According to the equation Q=VC, if voltage increases, capacitance should too... I'm missing something here... I apologize!

Homework Statement We start with a 2.50 μF capacitor connected to a power supply set to a voltage of 9.30 V. Then we increase the voltage on the power supply by 3.00 V. Now what is its capacitance? Homework Equations Q=ΔV*C The Attempt at a Solution The answer is 2.5 μF still, but WHY...

Several years late to the party, but I'm curious, was that last comment a hint that there IS a shortcut...?

That makes sense; thank you!

Homework Statement [/B] A 12 Volt lead-acid car battery, engineered for "up to 500 or more charge/discharge cycles," has a rating of 330.0 Ampere-hours. It sells for $ 262.00. Part B: The battery has a mass of 32.7 kg. What total mass of such batteries would be required to deliver the same...

That makes sense; it's just a bit odd to think about! Thank you.

I am sorry but I am a bit confused as to how to apply reflection symmetry as an argument...

Homework Statement I want to check my understanding of the symmetry arguments that allow for E to come out Gauss's Law and the symmetry arguments that allow for E vector *dA to become EdA. Specifically for an infinitely long cylinder. Homework Equations ∫EdA=q/ε The Attempt at a Solution So...

I understand. Thanks for your help.

Yup, I was pathetically and ridiculously confused too; my error lied in misreading problem statements. I am very sorry about that. To find total charge, dQ=λdl, which in this case dQ=-34*10^-9ydy. Integrate with respect to y from 0 to 2.9 and you get -34*10^-9(2.9^2)/2, which yields the correct...

I apologize for evidently not being clear enough. I used the equations that I stated in the relevant equations and, substituting information as stated in the attempt at a solution, and came up with ∫(k(34*10^-9)ydy)/.8 which, before being evaluated from 0 to 2.9, equals k(34*10^-9)y^2/2, with a...

Homework Statement A line of charge with a non-uniform charge density lambda=ay, where a=−34.00 nC/m^2 lies along the y axis in the region 0≤y≤2.90 m. Calculate the electric potential of this line of charge at point P on the x axis a distance 0.80 m from the origin. Assume the potential...