Recent content by Pqpolalk357

Could someone explain to me what is exactly is the "coupling force" ?

Homework Statement Two identical undamped oscillators, A and B, each of mass m and natural (angular) frequency $\omega_0$, are coupled in such a way that the coupling force exerted on A is \alpha m (\frac{d^2 x_A}{dt^2}), and the coupling force exerted on B is \alpha m (\frac{d^2...

Please explain to me how to proceed.

Do you know by any chance how to proceed ?

Can you explain to me how did you solve this question ? Thank you

Ok Thank you very much for all your help. Have a nice day.

4 times

We find R=$$\frac{1}{6} \times 10^6$$ but I don't understand the rest of the question.

I am having a problem now with the final question: Find the rate R at which the equilibrium is 1.5 pCi/liter (well below the EPA action level). At this value for R, how many times per day is the total volume of air of the room exchanged? I tried to solve the above differential equation and...

I think I found. Is it: $$\frac{\Delta x}{\Delta t}=\frac{1}{6}\times 10^6+0.5R-R\frac{x}{10^6}$$

So we have a=1/6*10^6. I still don't understand what is b ..

Sam is seeping into a room from the basement at a rate of $$\frac{1}{6} \times 10^6 \frac{\mathrm{pCi}}{\mathrm{hr}}$$ (pCi=picocuries). The room contains $$10^6$$ liters of air. (The rate was chosen so that the room reaches the EPA action level of $$4 \frac{pCi}{liter}$$ after $$24$$...