Recent content by prateek_34gem

i have got e=1/2 but thts wrong ans . Correct ans . is 2/3 is ans given in book wrong or i am wrong ??

but there are two balls lying at rest do i have to consider the motion of only one of thm or take them whole as one ?

Homework Statement Two equal balls are in contact on a table and are in equillibrium. A third ball collides with them simultaneously, symetrically and remains at rest after the impact. The coefficient of restitution is : A)2/3 B)3/2 C)1/3 D)1/2 Homework Equations The...

ohk , I got the answer. Here is how i got it : Let us assume that the particle moves a quarter. so its displacement will be 21/2r. Now since the force acts in the direction towards centre. so taking the component of displacement along force : 21/2rcos45. now using the same formula...

is answer 1.94s

F.scosX/t ??

You should always solve the projectile problem like this : Let it be projected at angle 'x' with horizontal. Then at instantaneous time 't'. Let initial velocity be 'a'. :- Along X- Direction u=acosx a=0 v=acosx s=acosxt Along Y- Direction u=asinx a= -g v=asinx-gt...

You should always solve the projectile problem like this : Let it be projected at angle 'x' with horizontal. Then at instantaneous time 't' : Along X- Direction u=1000cosx a=0 v=1000cosx s=1000cosxt Along Y- Direction u=1000sinx a= -g v=1000sinx-gt s=1000sinxt-1/2gt2...

sorry i think force is acting away from centre

Force is centripetal so i think it is acting towards centre. And it is moving in circular track. Do i have to take the component of force acting along displacement.

Power Question !Need Help Homework Statement A particle of mass 'm' is moving in a Circular path of constant radius 'r' such that it's centripetal acceleration is given by ac= k2rt2 where k is constant. The power delivered to the particle by the force acting on it is :- A) 2(pi)mk2r2t B)...

ya i got it . thnx a ton

Thanks a ton! You all are great . The site rocks.

Homework Statement Uniform chain of length 'L' and mass of 'M' is lying on smooth table and one third of it's length is hanging vertically down over the edge of the table. If 'g' is acceleration due to gravity , then work required to pull the hanging part onto the table is : A)MgL...

Homework Statement Uniform chain of length 'L' and mass of 'M' is lying on smooth table and one third of it's length is hanging vertically down over the edge of the table. If 'g' is acceleration due to gravity , then work required to pull the hanging part onto the table is : A)MgL...