calvert11
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Homework Statement
A hot air balloon is traveling vertically upward at a constant speed of 4.4 m/s. When it is 27 m above the ground, a package is released from the balloon.
The acceleration of gravity is 9.8 m/s^2.
a) After it is released, for how long is the package in the air.
b) What is its speed just before impact with the ground?
Homework Equations
x = x0 + v0t + 1/2at^2
v = v0 + at
The Attempt at a Solution
a)
0 = 27 + 4.4t + 1/2(-9.8)t^2
t = 2.839 s ***this answer is wrong.
Is it wrong because v0 should equal 0 and not 4.4?
b)
v = 4.4 - 9.8(2.839)
v = -23.42 m/s ***this answer is obviously wrong because t is wrong.
But, should v0 be zero in this case as well?