Recent content by PrideofPhilly

A = 2(pi)rL E[2(pi)rL] = Q/ε E = Q/ε[2(pi)rL] E = λ/2(pi)εr Is this correct?

Homework Statement A long, thin, straight wire of length L has a positive charge Q distributed uniformly along it. Use Gauss' Law to show that the electric field created by this wire at a radial distance r has a magnitude of E = λ/(2πεor), where λ = Q/L. (Hint: For a Gaussian surface, use a...

Homework Statement Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge, and in an instrument that measures magnitude and direction of the force exerted by object by the field. (a) The object has a charge of +20.0 C, and...

nevermind, i got it! thank you!

where did you get the 0.33 from?

2 degrees is right thank you!

Homework Statement The following table shows the daily high tem- peratures for a week in May. Determine the change in temperature each day. Sun. 76◦ Mon. 72◦ Tues. 80◦ Wed. 75◦ Thurs. 75◦ Fri. 74◦ Sat. 78◦ Find the net change in temperature (the...

Homework Statement A weather balloon is designed to expand to a maximum radius of 30 m when in flight at its working altitude where the air pressure is 0.033 atm and the temperature is 95 K. If the balloon is filled at atmospheric pres- sure and 462 K, what is its radius at lift-off...

So, d = P X MM/RT d = (0.7 atm)(20 g/mol)/(8.31 J/mol*K)(200 K) d= 0.008423586 2 L * 0.008423586 = 1.684717208E-5 kg KE = 1/2(1.68E-5)(499.227 m/s)^2 = 2.09 J (WRONG ANSWER) AM I USING THE WRONG UNITS OR DID I DO A MATH ERROR?

Oh...I got it. Thank you!

If you divide: 57.2 psi/0.81 = 70.6 psi ALSO NOT THE RIGHT ANSWER! The right answer is 55.8986 psi, so the pressure does get smaller.

I'm assuming multiply: So, 57.2 psi X 0.8102143758 = 46.3 psi BUT THIS IS NOT THE RIGHT ANSWER!

The ratio of T1/T2 = (257 K)/(317.2 K) = 0.8102143758

Homework Statement The internal energy of a monoatomic ideal gas such as neon is simply the total kinetic energy of all its atoms. What is the internal energy of 2 liters of neon at a temperature of 200 K and pressure of 0.7 atm? Homework Equations PV = nRT KE(ave) = 3/2kT U =...

Homework Statement A car tire gauge is used to fill a tire to a gauge pressure of 42.5 lb/in2 on a cold morning when the temperature is -16 C. Atmospheric pressure is 14.7 lb/in2 and 0 C = 273 K. What would the tire gauge read when the tire has been heated up to 44.2 C? Homework...