The Internal Energy of Neon Gas

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Homework Help Overview

The discussion revolves around calculating the internal energy of neon gas, a monoatomic ideal gas, given its volume, temperature, and pressure. Participants explore the relationship between kinetic energy and internal energy, while questioning the assumptions related to density and the application of relevant equations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to calculate internal energy using kinetic energy formulas and the ideal gas law. Questions arise regarding the accuracy of density calculations at the specified temperature and pressure, as well as potential errors in unit conversions and mathematical operations.

Discussion Status

Some participants provide alternative approaches to calculating density and internal energy, while others express uncertainty about their calculations. There is a recognition of the simplicity of the relationship between internal energy, pressure, and volume, but no consensus on the correct approach has been reached.

Contextual Notes

Participants note the need to consider the density of neon gas under non-standard conditions, as well as the implications of using standard temperature and pressure values in their calculations.

PrideofPhilly
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Homework Statement



The internal energy of a monoatomic ideal gas such as neon is simply the total kinetic energy of all its atoms.

What is the internal energy of 2 liters of neon at a temperature of 200 K and pressure of 0.7 atm?

Homework Equations



PV = nRT
KE(ave) = 3/2kT
U = 3/2nRT

The Attempt at a Solution



KE = 1/2mv^2

From a previous problem, I figured out that v(rms) = 499.227 m/s.

And, 2 liters of neon X 0.9002 g/L (density of neon) = 0.0018004 kg

KE = 1/2(0.0018004 kg)(499.227 m/s) = 224.3546833 J (wrong answer)

I feel like I am approaching this problem in the wrong manner. Please help!
 
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That's the density of Ne at STP. What is the density at 200K and .7 atm?
 
So, d = P X MM/RT

d = (0.7 atm)(20 g/mol)/(8.31 J/mol*K)(200 K)
d= 0.008423586

2 L * 0.008423586 = 1.684717208E-5 kg

KE = 1/2(1.68E-5)(499.227 m/s)^2 = 2.09 J (WRONG ANSWER)

AM I USING THE WRONG UNITS OR DID I DO A MATH ERROR?
 
PrideofPhilly said:
So, d = P X MM/RT

d = (0.7 atm)(20 g/mol)/(8.31 J/mol*K)(200 K)
d= 0.008423586

2 L * 0.008423586 = 1.684717208E-5 kg

KE = 1/2(1.68E-5)(499.227 m/s)^2 = 2.09 J (WRONG ANSWER)

AM I USING THE WRONG UNITS OR DID I DO A MATH ERROR?

I'd say your numbers are wrong, because without even looking you had .0018 kg using STP. I wouldn't expect such a small number after accounting for the 200/273 ratio and the .7 ratio.

Won't the approach work out to be more like (P1/T1)/(P2/T2) = d1/d2 ?
 
I may be missing something but it looks from the revelant equations that
U=1.5*(R/M)*T where R is the universal gas constant, M is the molecular weight of neon and T is temperature in deg K. Am I over simplifing this?
 
The solution to the problem is startlingly simple; you were less than a hair away from getting it. You wrote, as a relevant equation, U = 3/2nRT. You also wrote PV = nRT. So if U=(3/2)PV, and you have both P and V.

Remember this neat result: the internal energy of an ideal gas depends only on its pressure and volume.
 

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