Troubleshooting a Weather Balloon Expansion Problem

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Homework Help Overview

The problem involves a weather balloon's expansion, specifically calculating its radius at lift-off given certain atmospheric conditions and using the ideal gas law. The subject area includes thermodynamics and gas laws.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the ideal gas law and volume relationships. One participant attempts to calculate the number of moles and the radius, while another suggests an alternative approach that simplifies the problem by using the relationship between pressure, volume, and temperature without needing to find the number of moles. Questions arise regarding the mathematical reasoning behind the cube root used in the calculations.

Discussion Status

The discussion is active, with participants exploring different methods to approach the problem. Some guidance has been offered regarding the relationship between volume and radius, and clarification on mathematical expressions has been provided. There is no explicit consensus on the correct method yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is an ongoing exploration of assumptions related to the ideal gas law and the conditions at lift-off.

PrideofPhilly
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Homework Statement



A weather balloon is designed to expand to
a maximum radius of 30 m when in flight at
its working altitude where the air pressure is
0.033 atm and the temperature is 95 K.
If the balloon is filled at atmospheric pres-
sure and 462 K, what is its radius at lift-off?

Homework Equations



PV = nRT
Volume = 4/3πr^3

The Attempt at a Solution



First, I used the ideal gas law to find n:

(0.033)(4/3π(30)^3) = n(8.31)(95)
n = 4.727610453 mol

Then, I solved for r:

V = nRT/P
4/3πr^3 = (4.727610453)(8.31)(462)/1 atm
r = 11.30381236 m (WRONG ANSWER)

What am I doing wrong?
 
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So PV/T is constant, you don't actually need the number of moles.
V1 = (T1/P1) * (P2V2/T2)
= (462/1) * (0.033*V2/95)
V1 = 0.16 V2

So the ground volume is 16% off the final volume, an the radius goes as the cube root of volume, so the initial radius is 0.16^0.33 of 30m
 
where did you get the 0.33 from?
 
PrideofPhilly said:
where did you get the 0.33 from?

He means to the power of one third (the cube root, as he said).
 
nevermind, i got it! thank you!
 

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