Recent content by PsiPhi
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Geodesic equation in new coordinates question
Cheers, AEM. I do have Weinberg's text, I will have a look.- PsiPhi
- Post #3
- Forum: Advanced Physics Homework Help
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Geodesic equation in new coordinates question
Homework Statement Suppose \bar{x}^{\mu} is another set of coordinates with connection components \bar{\Gamma}^{\mu}_{\alpha\beta}. Write down the geodesic equation in new coordinates. Homework Equations Using the geodesic equation: 0 = \frac{d^{2}x^{\mu}}{ds^{2}} +...- PsiPhi
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- Coordinates Geodesic Geodesic equation
- Replies: 2
- Forum: Advanced Physics Homework Help
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Graduate Gauge invariance and it's relation to gauge bosons
Hello, I'm currently doing a project that is concerned with the hopeful discovery of the Higgs Boson at LHC. I'll be running some code that my supervisor has produced, but before that he wanted me to understand more of the physics that is behind the Higgs mechanism. He has proposed a...- PsiPhi
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- Bosons Gauge Gauge bosons Gauge invariance Invariance Relation
- Replies: 6
- Forum: High Energy, Nuclear, Particle Physics
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Schrodinger equation with Electric/Magnetic Potential
Hello again, I was wondering if you guys could check the logic of what I've done so far for the question I'm about to propose. I'm a little stuck on how to reduce the equation further: So here's the question: (ii) Separate variables and reduce the Schrödinger equation to a one dimensional...- PsiPhi
- Post #17
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Sweet thanks for all the help Gokul and dexter. There's a couple more parts to the overall question, I'm about to get started on these parts. If I get stuck again, I'll ask you guys. Thanks again, for all the help. Cheers.- PsiPhi
- Post #16
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Yep, you get 2 \vec{A} . \nabla . Then this will cancel out, just wondering if my final equation seems logical? With all the steps taken into account, also how about if A was equal to A = (0, 0, -xB) which still yields B = (0, B, 0)- PsiPhi
- Post #14
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Taking the Curl of (zB, 0, 0) it returns B = (0, B, 0), which agrees with the B field specified. But also, we can take the curl of (0, 0, -xB) and this yields B = (0, B, 0). Is the zB one correct or -xB one correct or both are correct? I'm thinking it has something to do with the symmetry of the...- PsiPhi
- Post #11
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Have you got a link I could look up on where they use Landau gauge? The gauges I'm familiar with are Coulomb and Lorenz only. thanks.- PsiPhi
- Post #8
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Hey, I've got the generalised quantum Hamiltonian for the case above. Now, I want to obtain the relevant scalar/vector potentials given the E/B fields specified above. I have solved the vector potential expression, and related all the corresponding B and A components to their respected...- PsiPhi
- Post #6
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Hey, Sorry I haven't replied in a few days. But, I've been flat out with other subjects. OK, back to this problem, I have found a solution to this where they used Lagrangian-Hamiltonian to formulate the solution. And it seems like they obtain a Hamiltonian of H = q\phi + \frac{1}{2m} \left[...- PsiPhi
- Post #4
- Forum: Advanced Physics Homework Help
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Schrodinger equation with Electric/Magnetic Potential
Homework Statement Consider a particle of charge e and mass m in crossed E and B fields, given by E = (0,0, E), B = (0,B, 0), r = (x, y, z). Write the Schrödinger equation. Homework Equations Schrödinger's equation: \left[ -\frac{\hbar^{2}}{2m} \nabla^{2} + V(r,t) \right] \Psi(r,t)...- PsiPhi
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- Potential Schrödinger Schrodinger equation
- Replies: 18
- Forum: Advanced Physics Homework Help
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Calculating Momentum Eigenstates of Spin in the Y Direction
Ah yes, you are correct. The eigenvector I did before was for -\frac{\hbar}{2}. But a weird thing happens, if i solve v_2 in terms of v_1 you will get a different eigenvector. However, I finally realized they differ by a multiplicative constant of i. Thanks for the help, olgranpappy.- PsiPhi
- Post #5
- Forum: Advanced Physics Homework Help
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Calculating Momentum Eigenstates of Spin in the Y Direction
For the eigenvalue \lambda = + \frac{\hbar}{2}, I get two simulatenous equations: -v_{1} + iv_{2} = 0 ... (1) iv_{1} - v_{2} = 0 ... (2) Solving (1) for v_{1} in terms of v_2: -v_{1} = iv_{2} v_{1} = -iv_{2} Therefore, looking at the comparison of v_{1} and v_2, the...- PsiPhi
- Post #3
- Forum: Advanced Physics Homework Help
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Calculating Momentum Eigenstates of Spin in the Y Direction
Homework Statement Starting with \sigma_{y}, calculate the momentum eigenstates of spin in the y direction. \sigma_{y} = \left[\stackrel{0}{i} \stackrel{-i}{0}\right] (Pauli spin matrix in the y direction) S_{y} = \frac{\hbar}{2}\sigma_{y} (spin angular momentum operator for the y direction)...- PsiPhi
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- Eigenstates Momentum Spin
- Replies: 4
- Forum: Advanced Physics Homework Help
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Newton's law of cooling for corpse
Homework Statement The time it takes for a deceased human body to reach room temperature. Room temperature = 25 degrees C Initial temperature of corpse = 37 degrees C Homework Equations I used Newton's law of cooling: \frac{dT}{dt} = -k(T - T_{room}) where T is a function of t(time in...- PsiPhi
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- Cooling Law Newton's law
- Replies: 2
- Forum: Calculus and Beyond Homework Help